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2 years ago

A line passes through the point (-4,8) and has a slope of 3/2. Write an equation in point slope form for this line.

Mathematics

1 answer:

Kay [80]2 years ago

5 0

Answer:

y-8=3/2(x+4)

Step-by-step explanation:

y-y1=m(x-x1)

y-8=3/2(x-(-4))

y-8=3/2(x+4)

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For f(x)=1/x^2-3, find<br> a) f(3)<br> b) f(2+h)<br> Show/explain work

valentina_108 [34]

$f(x)=\dfrac{1}{x^2-3}\\\\a)\ f(3)\to\text{put x=3 to the equation of the function f}\\\\f(3)=\dfrac{1}{3^2-3}=\dfrac{1}{9-3}=\dfrac{1}{6}\\\\Answer:\ \boxed{f(3)=\dfrac{1}{6}}\\\\b)\ f(2+h)\to\text{put x=2+h to the equation of a function f}\\\\f(2+h)=\dfrac{1}{(2+h)^2-3}\ \ \ |\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\=\dfrac{1}{2^2+2(2)(h)+h^2-3}=\dfrac{1}{4+4h+h^2-3}=\dfrac{1}{h^2+4h+1}\\\\Answer:\ \boxed{f(2+h)=\dfrac{1}{h^2+4h+1}}$

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2 years ago

Brainiest if correct

Mrac [35]

X=14
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2 years ago

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How much taller was Mt. Everest determined to be in 1999, than in 1852? 11 meters 12 meters 22 meters 147 meters

katen-ka-za [31]

Answer:

11 meters

Step-by-step explanation:

In 1852 its height was 29.002ft or 8.839m, while the measuring in 1999 said that it was 29.035ft or 8.850m. That means that it is taller by some 11 meters or 33 feet. That is because it keeps increasing its size since its positioned on such plates that hit each other.

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2 years ago

22x – 54 + 5.736x^4 - 2x^2<br> Standard form

Yuri [45]

Answer:

5.736x^4 - 2x^2 +22x - 54

Step-by-step explanation:

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2 years ago

A flat rectangular piece of aluminum has a perimeter of 62 inches. The length is 15

Salsk061 [2.6K]

Answer:

So, the required width of rectangular piece of aluminium is 8 inches

Step-by-step explanation:

We are given:

Perimeter of rectangular piece of aluminium = 62 inches

Let width of rectangular piece of aluminium = w

and length of rectangular piece of aluminium = w+15

We need to find width i.e value of x

The formula for finding perimeter of rectangle is: $Perimeter=2(Length+Width)\\$

Now, Putting values in formula for finding Width w:

$Perimeter=2(Length+Width)\\\\62=2(w+15+w)\\62=2(2w+15)\\62=4w+30\\62-30=4w\\4w=32\\w=\frac{32}{4}\\w=8$

After solving we get the width of rectangular piece :w = 8

So, the required width of rectangular piece of aluminium is 8 inches

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2 years ago