We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
Answer:
A=34, G=31
Step-by-step explanation:
G=A-3
2G+A=99
plug in for g 2(A-3)+A=99
distribute 2 A-3+A=99
combine like terms 3A-3=99
solve for a 3A=102 A=34
plug in a solve for g G=34-3 G=31
Hi there! The answer is about 23%
First we need to find the total amount of buttered popcorn sold. This is 182 + 140 + 97 = 419 buckets.
To find the percentage of the buttered popcorn buckets that were large, we use the following formula:

Filling in this formula brings us to our answer:

Hence, the answer is about 23%
Answer:
Isolate the variable by dividing each side by factors that don't contain the variable.
n=5, -5