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2 years ago

5 (x - 1) and (x + 2) are factors ofax3 - 2x2 – 5x + b. Determine thevalues of a and b.

Mathematics

1 answer:

netineya [11]2 years ago

7 0

Answer:

w nkekwo

Step-by-step explanation:

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Could someone help me with this please!

sertanlavr [38]

Angles 1, 3, and 4 make up a straight line.
Thus, 3x + 90 + 3x - 6 = 180 (angle sum of straight line)
6x - 6 = 90
6x = 96

x = 16
Now angle 1 becomes 3(16) = 48
Angle 1, 2, and 3 also make up a straight line.
Thus, angle 2 + 48 + 90 = 180
angle 2 + 138 = 180
angle 2, therefore, becomes 42. In essence, (A)

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2 years ago

Read 2 more answers

What is the length of D. 8ft

KengaRu [80]

Answer:

96 inches

Step-by-step explanation:

8 ft is 8(12) inches, which is 96 inches

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2 years ago

I need help I'm in high school algebra 2 and I have a quiz that I need to pass I need someone to help me. Its about adding and s

Tatiana [17]

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Step-by-step explanation:

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2 years ago

The number of coins on the third day will be 2x2x2. Can you write

ZanzabumX [31]

Answer:

$2^{3}$

Step-by-step explanation:

2*2*2 = $2^{3}$

5 0

3 years ago

Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2

drek231 [11]

Answer:

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is $x^{3}-2 x^{2}-x+2=0$

Solution:

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is

$F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0$

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

$F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0$

$\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}$

So, the equation is $x^{3}-2 x^{2}-x+2=0$

Let us put x = 0 in f(x) to check whether our answer is correct or not.

$\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2$

Hence, the equation of the polynomial is $x^{3}-2 x^{2}-x+2=0$

3 0

2 years ago

5 (x - 1) and (x + 2) are factors ofax3 - 2x2 – 5x + b. Determine thevalues of a and b.​

5 (x - 1) and (x + 2) are factors ofax3 - 2x2 – 5x + b. Determine thevalues of a and b.