What is the value of x?
1 answer:
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The only that has the shape of the one below.
y = -4(x^3 + 7x^2+8x - 16)
Let x = 1
y = - 4(1 + 7 + 8 - 16)
y = 0
y = -4(x -1)(x^2 + 8x + 16)
y = -4(x - 1)(x + 4)^2
y = -4(x^3 + 7x^2+8x - 16)
Let x = 1
y = - 4(1 + 7 + 8 - 16)
y = 0
y = -4(x -1)(x^2 + 8x + 16)
y = -4(x - 1)(x + 4)^2
Answer:
d ≈ 3.6 units
Step-by-step explanation:
calculate the distance d using the distance formula
d =
with (x₁, y₁ ) = (6, - 7 ) and (x₂, y₂ ) = (3, - 5 )
d =
=
=
=
=
≈ 3.6 ( to the nearest tenth )