All categories

2 years ago

HELP!!! Choose the best answer.

Mathematics

1 answer:

maxonik [38]2 years ago

4 0

Answer:

x^3y^2+x^2y^3-x^2-y^2

Step-by-step explanation:

I will edit my answer if you need my explanation.

If this has helped you please mark as brainliest

You might be interested in

Help solve equations by completing the square

Allushta [10]

$x^2+10x+22=13\\x^2+10x+22-13=0\\x^2+10x+9=0\\$

Now completing the square.

$(x^2+10x)+9=0\\(x^2+10x+25)+9-25=0\\(x+5)^2-16=0\\(x+5)^2=16$

(x+5)² = 16 is the rewritten equation... For first question btw.

For the solutions to the equation -

$x+5=\sqrt{16},-\sqrt{16} \\x+5=4,-4\\x=4-5,-4-5\\x=-1,-9$

x = -1,-9 is the solution, for the second question.

5 0

2 years ago

Write the domain and range as an inequality.

BaLLatris [955]

Answer:

Step-by-step explanation:

domain is (-3,x) x- inter

range is (x,2) y-inter

4 0

2 years ago

Solve the following equation for h. r+3Q/h=t

Arada [10]

Answer:

$\bold{h=\dfrac{3Q}{t-r}}$

Step-by-step explanation:

$\bold{r+\frac{3Q}h=t}\\-r\qquad\ -r\\\bold{\frac{3Q}h=t-r}\\\cdot h\qquad \cdot h\\ \bold{3Q=(t-r)h}\\^{\div(t-r)\quad\div(t-r)}\\\bold{\dfrac{3Q}{t-r}=h}$

Or, if you mean (r+3Q)/h=t:

$\bold{\frac{r+3Q}h=t}\\{}\ \ \cdot h\quad\ \cdot h\\\bold{r+3Q=ht}\\{}\ \ \div t\qquad \div t\\\bold{\dfrac{r+3Q}{t}=h}\\\\\bold{h=\dfrac{r+3Q}{t}}$

4 0

2 years ago

For each shape, write an algebraic expression for its perimeter - part A and B

nikitadnepr [17]

Answer:

a) p + q + r

b) 2(a + b)

Step-by-step explanation:

The perimeter of a two-dimensional shape is the distance all the way around the outside.

An algebraic expression contains one or more numbers, variables, and arithmetic operations.

A variable is a symbol (usually a letter) that represents an unknown numerical value in an equation or expression.

Question (a)

The length of each side of the triangle is labeled p, q and r. Therefore, the perimeter is the sum of the sides:

Perimeter = p + q + r

So the algebraic expression for the perimeter of the triangle is:

p + q + r

Question (b)

Not all of the sides of the shape have been labeled.

However, note that the horizontal length labeled "a" is equal to the sum of "c" and the horizontal length with no label.

Similarly, note that the vertical length labeled "b" is equal to the sum of "d" and the vertical length with no label.

Therefore, the perimeter is twice the sum of a and b:

Perimeter = 2(a + b)

So the algebraic expression for the perimeter of the shape is:

2(a + b)

5 0

1 year ago

Show that the equation x^4/2021 − 2021x^2 − x − 3 = 0 has at least two real roots.

andreev551 [17]

The roots of an equation are simply the x-intercepts of the equation.

See below for the proof that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ has at least two real roots

The equation is given as: $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$

There are several ways to show that an equation has real roots, one of these ways is by using graphs.

See attachment for the graph of $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$

Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)

From the attached graph, we can see that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ crosses the x-axis at approximately -2000 and 2000 between the domain -2500 and 2500

This means that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ has at least two real roots

Read more about roots of an equation at:

brainly.com/question/12912962

6 0

2 years ago