Answer:
2 11/15
Step-by-step explanation:
Let X equal the decimal number
Equation 1:
X=2.73¯¯¯(1)
With 1 digits in the repeating decimal group,
create a second equation by multiplying
both sides by 101 = 10
Equation 2:
10X=27.33¯¯¯(2)
Subtract equation (1) from equation (2)
10XX9X===27.33...2.73...24.6
We get
9X=24.6
Solve for X
X=24.69
Multiply to eliminate 1 decimal places.
Here you multiply top and bottom by 1 10's
= 101 = 10
24.69×1010=24690
Find the Greatest Common Factor (GCF) of 246 and 90, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 6,
246÷690÷6=4115
Simplify the improper fraction,
=21115
In conclusion,
2.73¯¯¯=2 11/15
Answer:
5 and 13
Step-by-step explanation:
Answer:
![\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D)
Step-by-step explanation:
We are required to simplify the quotient: ![\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B20%7D%7D)
Since the <u>numerator and denominator both have the same root index</u>, we can therefore say:
![\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}} =\sqrt[3]{\dfrac{60} {20}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B20%7D%7D%20%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B60%7D%20%7B20%7D%7D)
![=\sqrt[3]{3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B3%7D)
The simplified form of the given quotient is .
<em>Answer:</em>
<em>1cm = 50
</em>
<em>2 cm = 50 x 2
</em>
<em>3cm = 50 x 3
</em>
<em>and the inverse:50m = 50/50 = 1cm
</em>
<em>100m = 100/50 = 2cm
</em>
<em>150m = 150/50 = 3cm
</em>
<em>381m = 381/
</em>
