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abruzzese [7]
3 years ago
13

Leo went to the store to buy ingredients for his vegetable stew.He purchased 1.79 Lbs of potatoes and 2.34 Lbs of carrots for th

e stew.How many pounds of vegetables did Leo purchase at the store?
Mathematics
1 answer:
natta225 [31]3 years ago
7 0
He purchased 4.13 pounds of vegetables.
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The Gainey’s are going to start their savings by saving $10 on the first day and then 10 each day of the month
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is there more to this? if so i would love to help.

7 0
3 years ago
A consumer agency is investigating the blowout pressures of Soap Stone tires. A Soap Stone tire is said to blow out when it sepa
Likurg_2 [28]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: Impact force needed for Sap Stone tires to blow out. (foot-pounds)

n= 29, S= 1358 foot-pound

a)

Soap Stone claims that "The tires will blow out at an average pressure of μ= 26000 foot-pounds with a standard deviation of σ= 1020 foot-pounds.

According to the consumer's complaint, the variability of the blown out forces is greater than the value determined by the company.

I)

Then the parameter of interest is the population variance (or population standard deviation) and to test the consumer's complaint you have to conduct a Chi-Square test for σ².

σ²= (1020)²= 1040400 foot-pounds²

H₀: σ² ≤ 1040400

H₁: σ² > 1040400

α: 0.01

II)

X^2= \frac{(n-1)S^2}{Sigma^2} ~~X^2_{n-1}

X^2_{H_0}= \frac{(n-1)S^2}{Sigma^2}= \frac{(29-1)*(1358)^2}{1040400} = 49.63

III)

This test is one-tailed to the right and so is the p-value. This distribution has n-1= 29-1= 28 degrees of freedom, so you can calculate the p-value as:

P(X²₂₈≥49.63)= 1 - P(X²₂₈<49.63)= 1 - 0.99289= 0.00711

⇒ The p-value is less than the significance level so the test is significant at 1%. You can conclude that the population variance of the blowout forces is less than 1040400 foot-pounds², at the same level the population standard deviation of the blow out forces is less than 1020 foot-pounds.

b)

99% CI for the variance. Using the X² statistic you can calculate it as:

[\frac{(n-1)S^2}{X^2_{n-1;1-\alpha /2}} ;\frac{(n-1)S^2}{X^2_{n-1;\alpha /2}} ]

X^2_{n-1;\alpha /2}= X^2_{28; 0.005}= 13.121

X^2_{n-1;1-\alpha /2}= X^2_{28; 0.995}= 49.588

[\frac{28*(1358)^2}{49.588} ;\frac{28*(1358)^2}{13.121} ]

[1041312.253; 3935415.898] foot-pounds²

I hope this helps!

3 0
3 years ago
A group of students were surveyed to find out if they like working as a camp counselor and/or as a lifeguard during summer break
MAXImum [283]
I believe that Coralle is right 
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3 years ago
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James earned $361.36 for working last week and $347.85 for working this week. What was the total amount he earned?
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$361.36 for week one + $347.85 for week two = $709.21 total for both weeks
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3 years ago
Can someone please help with this question pleaseee
Ulleksa [173]

Answer: Choice C) 10.5

The distance from A to C is 7 units (count out the spaces between the two points, or subtract y coordinates 4-(-3) = 4+3 = 7)

Let AC = 7 be the base of the triangle. You might want to rotate the image so that AC is laying horizontally rather than being vertical.

Now move to point P. Walk 3 spaces to the right until you land on segment AC. This shows that the height of the triangle is 3 when the base is AC = 7.

base = 7, height = 3

area of triangle = (1/2)*base*height

area of triangle = 0.5*7*3

area of triangle = 10.5 square units

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3 years ago
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