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luda_lava [24]
3 years ago
6

Solve: y = -7(-13) it said 21 was wrong

Mathematics
1 answer:
White raven [17]3 years ago
4 0

Answer: y = 91

Step-by-step explanation:

y = -7(-13)

y = -7 x -13

y = 91

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Use the substitution method to solve this system.<br> y = 2x+4<br> 3x+y = 9
dexar [7]

Answer:

x = 1; y=6

Step-by-step explanation:

y = 2x +4

3x + y = 9

Substitute 2x+4 for y in 3x+y = 9

3x + y = 9

3x + 2x+4 = 9

5x + 4 = 9

5x = 9-4

5x = 5

5x/5 = 5/5

x = 1

Substitute 1 for  x in y = 2x +4

2(1) + 4

2 + 4

= 6

Answered by Gauthmath

3 0
3 years ago
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Lesson 8.8: Angle Relationship
Semmy [17]

Answer:

Step-by-step explanation:

what is the question that its asking?

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4 years ago
A complex number, (a + bi), multiplied by (2 + 3i) and added to -i gives the product of (-11 + 5i) and (1 – i).
Novosadov [1.4K]
(a+bi)(2+3i)-i=(-11+5i)(1-i)
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(2a-3b)+(3a+2b-1)i=-6+16i
Therefore; we have the next system of equations:
2a-3b=-6
3a+2b-1=16

Finally, the system of equations is:
2a-3b=-6
3a+2b=17
We can solve this system of equations by reduction method
 2(2a-3b=-6) 
 3(3a+2b=17)
----------------------
   13a=39  ⇒a=39/13=3

 3(2a-3b=-6)
-2(3a+2b=17)
----------------------
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3 years ago
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Find a positive number for which the sum of it and its reciprocal is the smallest​ (least) possible. Let x be the number and let
Allisa [31]

Answer:

S(x) = x + \frac{1}{x} --- Objective function

Interval = \{x:x=1\}

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

x + \frac{1}{x}

Hence, the objective function is:

S(x) = x + \frac{1}{x}

To get the the interval, we start by differentiating w.r.t x

<em>Using first principle, this gives:</em>

S'(x) = 1 - \frac{1}{x^2}

Equate S'(x) to 0 in order to solve for x

0 = 1 - \frac{1}{x^2}

Subtract 1 from both sides

0 -1 = 1 -1 - \frac{1}{x^2}

-1 = - \frac{1}{x^2}

Multiply both sides by -1

1 = \frac{1}{x^2}

Cross Multiply

x^2 * 1 = 1

x^2  = 1

Take positive square root of both sides because x is positive

\sqrt{x^2} = \sqrt{1

x = 1

Representing x using interval notation, we have

Interval = \{x:x=1\}

To get the smallest sum, we substitute 1 for x in S(x) = x + \frac{1}{x}

S(1) = 1 + \frac{1}{1}

S(1) = 1 + 1

S(1) = 2

<em>Hence, the smallest sum is 2</em>

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4 years ago
Graph the function y = |x +31 - 2.
adoni [48]

Answer:

Step-by-step explanation:

3 0
3 years ago
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