Hello,
answer is C
m=-40h+130
Indeed
A=(1/2,110)
B=(3,10)
y-10=(10-110/(3-1/2)(x-3)
==>y=-100/(5/2)*(x-3) +10
==>y=-40x+120+10
==>y=-40x+130
(or m=-40h+130 )
First of all we need to formulate two equations.
x = monthly fee per minute
y = monthly fee per minute over 500
500x + 130y = $53.55
500x + 209y = $63.03
Since we know that 500x = $53.55 - 130y we can substitute.
($53.55 - 130y) + 209y = $63.03
79y = 9.48
y = $0.12
Now we can substitute y into the other equation.
500x = $53.55 - 130(0.12)
500x = $53.55 - $15.6
500x = $37.95
So the answer is $37.95 monthly for 500 minutes with an over quota fee of $0.12 per minute.
First look at the equation : s+7= 14
subtract 7 and move to the right : s= 14-7
combine 14-7 : s=7
Answer is : s=7
Answer:frffvftv
Step-by-step explanation:
Answer:
Answer 4, the bottom right answer
Step-by-step explanation:
Question was pretty blurry so I had to write it out:
The school Spanish Club is holding a car wash to raise $200 to attend a conference. After spending $10 on supplies, the club will was cars for donations of $4 each.
The situation can be modeled by the inequality 4z-10≥200, which has the solution z≥52.5. What is the best way to interpret this solution?
1. At least 53 members of the Spanish Club must volunteer to help at the car wash.
2. The Spanish Club should have spent at least $52.50 on supplies.
3. The Spanish Club needs $52.50 more to meet its goal.
4. The Spanish Club must wash at least 53 cars to meet its goal.
The answer would be 4, because the inequality is saying 4 dollars times the number of cars minus 10 dollars (for supplies) has to be greater than or equal to their goal of 200 dollars they want to raise.
Another way to explain: The 4z would represent how much money they would make for all the cars they wash, but they have to subtract 10 dollars for the supplies. This total has to be equal to or more than their goal of 200 dollars.
