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Klio2033 [76]
3 years ago
12

407.10 euros to pounds ​

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
3 0

Answer:

361.27 Pound sterling

Step-by-step explanation:

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<span>5(x - 2) + 2x
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If an = 2n - 8, then which one is not a term of the sequence? ( an means nth term)
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URGENT! WILL GIVE BRAINLIEST!!
IgorC [24]

Answer:

Option C) a_{n}=m-b+m(n-1) for n={\{1,2,3,...}\} is not the correct way to define the given infinite sequence

{\{m+b,2m+b,3m+b,4m+b,...}\}

Step-by-step explanation:

Given infinite sequence is {\{m+b,2m+b,3m+b,4m+b,...}\}

Option B) a_{n}=m-b+m(n-1) for n={\{1,2,3,...}\} is not the correct way to define the given infinite sequence {\{m+b,2m+b,3m+b,4m+b,...}\}

Now verify  a_{n}=m-b+m(n-1) for n={\{1,2,3,...}\} is true for the given infinite sequence

That is put n=1,2,3,.. in the above function

a_{n}=m-b+m(n-1)

When n=1,  a_{1}=m-b+m(1-1)

=m-b+0

a_{1}=m-b\neq m+b

When n=2,  a_{2}=m-b+m(2-1)

=m-b+m

a_{2}=2m-b\neq 2m+b

When n=3,  a_{3}=m-b+m(3-1)

=m-b+2m

a_{3}=3m-b\neq 3m+b

and so on.

Therfore a_{n}=m-b+m(n-1) for n={\{1,2,3,...}\} is not the correct way to define the given infinite sequence

{\{m+b,2m+b,3m+b,4m+b,...}\}

Therefore option C) is correct

5 0
4 years ago
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