All categories

3 years ago

You invest $1,000,000 in an account paying 12% compounded continuously, how much will you have in the account after 4 years?

Mathematics

2 answers:

romanna [79]3 years ago

7 0

I think you would have 2,083,333,23

Nadusha1986 [10]3 years ago

5 0

I belive you would have 2,083,333.25

You might be interested in

What is the slope of this equation? <br> 5y = -4 + 3x

BigorU [14]

Answer:

3/5

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Jack ran 13.5 miles in 1.5 hours. What was his speed in miles per minute?

Minchanka [31]

Answer:

Step-by-step explanation:

13.5 / 1.5 = 9

8 0

3 years ago

Read 2 more answers

In 2009, a school population was 1,700. By 2017 the population had grown to 2,500. Assume the population is changing linearly. W

qaws [65]

Answer:

100

Step-by-step explanation:

The population is changing linearly. This means that the population is increasing by a particular value n every year.

From 2009 to 2017, there are 8 increases and so, the population increases by 8n.

The population increased from 1700 to 2500. Therefore, the population increase is:

2500 - 1700 = 800

This implies that:

8n = 800

=> n = 800/8 = 100

The average population growth per year is 100.

4 0

3 years ago

6⋅[(32−8)÷4+2] What is the answer to this expession?

Nimfa-mama [501]

Answer:

Step-by-step explanation:

=6*[24/4+2]

=6*[6+2]

=6*8

=48

4 0

3 years ago

A 20% apple juice drink is mixed with a 100% apple juice drink. The function f(x)=(2)(1.0)+x(0.2)2+x models the concentration of

luda_lava [24]

Answer:

17.5

Step-by-step explanation:

Given that:

20% apple juice drink is mixed with a 100% apple juice drink.

$f(x)=\dfrac{(2)(0.1)+x(0.2)}{2+x}$

represents the concentration of apple juice in the drink when $x$ gallons of 20% drink are added to 2 gallons of pure juice.

Also, given that 6 gallons of 20% drink are added to the 2 gallons of pure juice.

To find:

The concentration of apple juice in the drink = ?

Solution:

Given the function:

$f(x)=\dfrac{(2)(0.1)+x(0.2)}{2+x}$

and

$x=6\ gallons$

$f(x)=\dfrac{(2)(0.1)+6(0.2)}{2+6}\\\Rightarrow f(x)=\dfrac{0.2+1.2}{8}\\\Rightarrow f(x)=\dfrac{1.4}{8}\\\Rightarrow f(x)=\bold{0.175}$

In percentage, the concentration 17.5.

7 0

3 years ago