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grigory [225]
3 years ago
13

If 12 Out of 30 people prefer KitKat bars over almond joy,how many people out of 330 would you predict would prefer KitKat.

Mathematics
2 answers:
miv72 [106K]3 years ago
8 0

The empirical probability that people would prefer KitKat is 12/30, or 0.4.

Then, among 330 people, 0.4(330 people), or 132, would prefer KitKat.

polet [3.4K]3 years ago
4 0
I would say 112. Because if 12 out of 30 people prefer KitKat bars then 112 would prefer 330
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tickets for a football match are sold at $30 for adults and $15 for children a company bought 28 tickets if x of these tickets w
anzhelika [568]
First, we must let:
   x = number of tickets intended for adults
   y = number of tickets intended for children.

a. Write in terms of x the number of tickets for children
     Solution:
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       To answer in terms of x:
           no. of tickets for tickets for children = 28 - x

b. the amount spent on tickets for adults
    Solution:  $30 is the cost of ticket per adult and there are x number of tickets intended for adults.
           Therefore, 
            amount spent on ticket for adults = 30x

c. the amount spent on the tickets.
     Solution:
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       $ 30 = cost of ticket per adult

      total amount spent on tickets = 30x + 15y    ⇒   (equation2)
  substitute equation 1 to equation 2.
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  (equation 2)   total amount spent on tickets = 30x + 15y
                        total amount spent on tickets = 30x + 15(28-x)
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3 years ago
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Alja [10]

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Random sampling refers to a sampling technique whereby each sample has an equal chance of being selected. It is an unbiased representation of the entire population and this is vital in drawing conclusion.

From the options given, the best way to randomly choose these 200 employees will be to use employee identification numbers to randomly select 200 employees.

7 0
3 years ago
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