All categories

3 years ago

I need help plz someone

Mathematics

1 answer:

stich3 [128]3 years ago

6 0

Answer:

5C 6D

Step-by-step explanation:

5, a^2 = b^2 + c^2

A is wrong because two distinct lines intersect at 1 point only or 0 (they will never intersect when they are parallel)

B & C are wrong because lines contain infinite point

E is wrong because 2 parallel lines will never intersect, as the result, their common points = 0

You might be interested in

Analyze the diagram below and complete the instructions that follow.

Phantasy [73]

Answer:

Option (B)

Step-by-step explanation:

From the figure attached,

ΔBCD and ΔACE are the similar triangles.

Therefore, by the property of similar triangles, corresponding sides of these similar triangles will be proportional.

$\frac{AC}{BC}= \frac{EC}{DC}$

$\frac{AB+BC}{BC}= \frac{ED+DC}{DC}$

$\frac{AB+6}{6}= \frac{24+8}{8}$

$\frac{AB+6}{6}= \frac{32}{8}$

$\frac{AB+6}{6}=4$

AB + 6 = 24

AB = 18

Option (B) will be the answer.

3 0

2 years ago

Help me please please

Studentka2010 [4]

Answer:

It's going to be B and E because it's in the hundreds place not in the tens or whole

6 0

2 years ago

Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate

yKpoI14uk [10]

Answer:

a) 0.5588

b) 0.9984

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24

Standard Deviation, σ = 6.4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(score between 20 and 30)

$P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{6.4} \leq z \leq \displaystyle\frac{30-24}{6.4}) = P(-0.62 \leq z \leq 0.94)\\\\= P(z \leq 0.94) - P(z < -0.62)\\= 0.8264 - 0.2676 = 0.5588 = 55.88\%$

$P(20 \leq x \leq 30) = 55.88\%$

b) Sampling distribution

Sample size, n = 22

The sample will follow a normal distribution with mean 24 and standard deviation,

$s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{6.4}{\sqrt{22}} =1.36$

c) P(mean score of sample is between 20 and 30)

$P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{1.36} \leq z \leq \displaystyle\frac{30-24}{1.36}) = P(-2.94 \leq z \leq 4.41)\\\\= P(z \leq 4.41) - P(z < -2.94)\\= 1 - 0.0016 = 0.9984 = 99.84\%$