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Brums [2.3K]
3 years ago
6

I need help plz someone

Mathematics
1 answer:
stich3 [128]3 years ago
6 0

Answer:

5C 6D

Step-by-step explanation:

5, a^2 = b^2 + c^2

6,

A is wrong because two distinct lines intersect at 1 point only or 0 (they will never intersect when they are parallel)

B & C are wrong because lines contain infinite point

E is wrong because 2 parallel lines will never intersect, as the result, their common points = 0

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The mean of 10 values is 19. If further 5 values are
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Answer:

22

Step-by-step explanation:

Pretend the 10 values in the first sentence are a,b,c,d,e,f,g,h,i,j

Pretend the addition 5 values is k,l,m,n,o

So the mean of all the 15 data is (a+b+c+d+e+f+g+h+i+j+k+l+m+n+o)/15=20

So the sum of all 15 data is  a+b+c+d+e+f+g+h+i+j+k+l+m+n+o=300                since 15(20)=300

Now let's look at the first 10:  We have their mean so we can write:

(a+b+c+d+e+f+g+h+i+j)/10=19

so a+b+c+d+e+f+g+h+i+j=190                               since 10(19)=190

So that means using our first sum equation and our equation sum equation we have

190+k+l+m+n+o=300

      k+l+m+n+o=300-190

      k+l+m+n+o= 110

So the average of those 5 numbers mentioned in your problem is 110/5=22

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Step-by-step explanation:

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