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3 years ago

Identify tan P as a fraction and as a decimal rounded to the nearest hundredth. HELP PLEASE!!

Mathematics

1 answer:

irakobra [83]3 years ago

8 0

$tangent=\dfrac{opposite}{adjacent}$

We have:

$opposite=8.5\\adjacent=16$

Substitute:

$\large\boxed{\tan P=\dfrac{8.5}{16}\approx0.53}$

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On Tuesday the mailman delivers 3 checks for $5 each and 2 bills for each .if you had a starting balance of $25 , what is the en

ycow [4]

5x3=15 25+15=40 40-10=30

6 0

3 years ago

Helppp? dont guess. pleaseeeee

N76 [4]

Answer:

12/100

Step-by-step explanation:

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2 years ago

If you need 8 oz of chocolate chips to make 1.6 lb of cookie dough how many ounces of chocolate chips will you need to make 7 lb

iren [92.7K]

Answer:

3.5 Oz of chocolate

Step-by-step explanation:

1.6 lb of cookie dough is made from chocolate of 8 Oz

1 lb will be made by 8/ 1.6 = 0.5 Oz of chocolate

Therefore

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3 years ago

Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract

anyanavicka [17]

Answer:

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8$

Step-by-step explanation:

The sum you are trying to understand is this.

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}$

Remember that in general when you have a geometric series

$\sum\limits_{n = 0}^{\infty} a*r^n$ you have that

$\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}$ and that equality is true as long as $|r| < 1$ .

Therefore here we have

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n$ and $\big|\frac{-1}{15} \big| = \frac{1}{15} < 1$

Therefore we can use the formula and

$\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n = \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16 = 15/8$

5 0

3 years ago

14. Write a two-column proof.

scZoUnD [109]

Given:

$\bold{ 8x=4y-20} \\\\ \bold{ y=13}$

Prove:

$\bold{x=4}$

Solution:

$\to \bold{8x=4y-20}..........(i)\\\\\to \bold{ y=13}........................(ii)$

Putting the value of equation (ii) into the equation (i):

$\to \bold{8x=4(13)-20}\\\\\to \bold{8x=52-20}\\\\\to \bold{8x=32}\\\\\to \bold{x=\frac{32}{8}}\\\\\to \bold{x= 4}\\\\$

putting the value x into the equation (i):

$\to \bold{8(4)=4y-20}\\\\\to \bold{32=4y-20}\\\\\to \bold{32+20=4y}\\\\\to \bold{52=4y}\\\\\to \bold{y=\frac{54}{4}}\\\\\to \bold{ y= 13.5}$

Therefore, the value of x= 4

Learn more:

brainly.com/question/6219408

3 0

2 years ago