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Harman [31]
3 years ago
8

I need help with these questions plz help

Mathematics
1 answer:
stepladder [879]3 years ago
6 0

Answer:

1.A=bh/2

2A=bh

2A/b=h

  answer                   check

2.f(x)=21-6x               f(5)=21-6(5)            

 g(x)=2x/5-11            f(5)=21-30

21-6x=2x/5-11            f(5)=-9

21=32x/5-11              g(5)=2(5)/5-11

(5)32=32x/5(5)         g(5)= 10/5-11

160=32x                    g(5)=2-11

5=x                             g(5)=-9

3. f(7)=3(7)-7

   f(7)= 21-7

   f(7)= 14

Step-by-step explanation:

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Andrea earned 200 points on a school assignment. Because the
Lera25 [3.4K]

Answer:

It was approximately a 9% decrease. (If you need to round to the nearest tenth, 9.1. If you need to round to the nearest hundredth, 9.10).

Step-by-step explanation:

I am going to assume that the question means that Andrea could have earned 220 points on the assignment, but instead because the assignment was late, she was marked down 20 points. (Reduced to 20 points is kind of awkward wording).

Given that, 20 divided by 220 comes out to 0.0909 repeating.

0.09, as a percentage, is 9%. (Again, 0.0909, 9.09%, could be rounded up to 9.1%).

Hope this helps!

7 0
3 years ago
Jerry has 25 weeks left to save $2,320 for a trip. If he saves an equal
Gwar [14]
Divide 25 by 2320 to get $92.80. 
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Read 2 more answers
25 POINTS!
WITCHER [35]

Answer:

The cosine of the angle is: negative

The sine of the angle is: positive

Step-by-step explanation:

5 0
3 years ago
Given f(x)=1/x+5 and g(x)=x-2
vladimir1956 [14]

For this case we have the following functions:

f (x) = \frac {1} {x + 5}\\g (x) = x-2

We must find f (g (x)). So:

f (g (x)) = \frac {1} {(x-2) +5} = \frac {1} {x-2 + 5} = \frac {1} {x + 3}

Finally we have to:

f (g (x)) = \frac {1} {x + 3}

For the function to be defined the denominator must be different from 0. That is x different from -3.

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Option B

3 0
3 years ago
Please help. Thank you​
love history [14]

Answer:

The length of side x is x = \sqrt{6}

Step-by-step explanation:

Pythagorean Theorem:

In a right triangle, with sides a and b, and hypothenuse h, we have that:

a^2 + b^2 = h^2

In this question:

The vertical line on the sides means that both are equal, that is, measuring x, so a = b = x.

Hypothenuse is the square root of 12. So h = \sqrt{12}

x^2 + x^2 = (\sqrt{12})^2

2x^2 = 12

x^2 = \frac{12}{2}

x^2 = 6

x = \sqrt{6}

The length of side x is x = \sqrt{6}

8 0
3 years ago
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