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Kazeer [188]
3 years ago
13

⚠️❗️⚠️❗️⚠️❗️10-22 POINTS PLEASE HELP ASAP I NEED THE ANSWER TO THE PROBLEM ANSWERED BELOW ⚠️❗️⚠️❗️⚠️❗️

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
8 0

Answer:

110

Step-by-step explanation:

Multiply 2*6 to get 12 then 7*14 to het 98 add those together and you get 110

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4 years ago
Write a polynomial f (x) that satisfies the given conditions. Polynomial of lowest degree with zeros of -4 (multiplicity 3), 1 (
yuradex [85]

Answer:

Step-by-step explanation:

Polynomial f(x) has the following conditions: zeros of -4 (multiplicity 3), 1 (multiplicity 1), and with f(0) = 320.

The first part zeros of -4 means (x+4) and multiplicity 3 means (x+4)^3.

The second part zeros of 1 means (x-1) and multiplicity 1 means (x-1).

The third part f(0) = 320 means substituting x=0 into (x+4)^3*(x-1)*k =320

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k = -5

Combining all three conditions, f(x)

= -5(x+4)^3*(x-1)

= -5(x^3 + 3*4*x^2 + 3*4*4*x + 4^3)(x-1)

= -5(x^4 + 12x^3 + 48x^2 + 64x - x^3 - 12x^2 - 48x - 64)

= -5(x^4 + 11x^3 + 36x^2 + 16x -64)

= -5x^3 -55x^3 - 180x^2 - 80x + 320

8 0
3 years ago
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