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Fantom [35]
3 years ago
13

How do you do this problem

Mathematics
1 answer:
garri49 [273]3 years ago
7 0

Answer:

110

Step-by-step explanation:

8x10=80

Area of triangle= 1/2 base times height

3x10=30

80+30=110

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4. Represent the following sets in Roster form.
Phoenix [80]

The roster form of the given sets are:

(i) A = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19}.

(ii) B = {1, 2, 3, 4, 5, 6, 7}.

(iii) C = {27, 64}.

(iv) D = {-1, 0, 1}.

The roster form of any set is the set with all elements of the set written in the set.

In the question, we are asked to represent the known sets in the roster form.

(i) A=The set of all odd natural numbers less than 20.

The set of all natural numbers, that is numbers after 1.

Odd numbers are numbers of the form 2n - 1.

Thus, the roster form is: A = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19}.

Going similarly to the others, we will get:

(ii) B={y: y = n, n ∈ N, n ≤7}

Roster form is, B = {1, 2, 3, 4, 5, 6, 7}.

(iii) C = {x: x is a perfect cube, 8 < x < 125}

Roster form is, C = {27, 64}.

(iv) D= {x: x ∈ Z, -2 < x < 2}​.

The roster form is, D = {-1, 0, 1}.

Learn more about the roster form of a set at

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6 0
1 year ago
1/2x + 5y- 10&lt; 0 The point (4,y) is a solution for the inequality shown. What is the value for y.
finlep [7]
Subtract x on both sides the result you divide it by 5
8 0
3 years ago
Read 2 more answers
A clinical trial was conducted to test the effectiveness of the drug zopiclone for treating insomnia in older subjects. Before t
aleksklad [387]

Answer:

We cannot say that the mean wake time are different before and after the treatment, with 98% certainty. So the zopiclone doesn't appear to be effective.

Step-by-step explanation:

The goal of this analysis is to determine if the mean wake time before the treatment is statistically significant. The question informed us the mean wake time before and after the treatment, the number of subjects and the standard deviation of the sample after treatment. So using the formula, we can calculate the confidence interval as following:

IC[\mu ; 98\%] = \overline{y} \pm t_{0.99,n-1}\sqrt{\frac{Var(y)}{n}}

Knowing that t_{0.99,15} = 2.602:

IC[\mu ; 98\%] = 98.9 \pm 2.602\frac{42.3}{4} \Rightarrow 98.9 \pm 27.516

IC[\mu ; 98\%] = [71.387 ; 126,416]

Note that 102.8 \in [71.384 ; 126.416] so we cannot say, with 98% confidence, that the mean wake time before treatment is different than the mean wake time after treatment. So the zopiclone doesn't appear to be effective.

7 0
3 years ago
A random sample of 16 statistics examinations was taken. The average sample score was 76.2 with a sample variance of 144. The 99
dlinn [17]

99% confidence interval for the population average examination score is between a lower limit of 67.35 and an upper limit of 85.05. The correct option is C.

<h3>What is the margin of error in statistics?</h3>

The margin of error is a statistic that describes how much random sampling error there is in survey results. One should have less faith that a poll's findings would accurately reflect those of a population census the higher the margin of error.

The interval will be calculated as below:-

Confidence interval = mean +/- margin of error (E)

mean = 76.2

variance = 144

sd = sqrt(variance) = sqrt(144) = 12

n = 16

Degree of freedom (df) = n - 1 = 16- 1 = 15

Confidence level (C) = 99% = 0.99

Significance level = 1 - C = 1 - 0.99 = 0.01 = 1%

t-value corresponding to 15 df and 1% significance level is 2.95

The margin of error will be:-

E = t×sd/√n = 2.95 ×  12/√16 = 8.85

The interval will be:-

Lower limit = mean - E = 76.2 - 8.85 = 67.35

Upper limit = mean + E = 76.2 + 8.85 = 85.05

Therefore, the 99% confidence interval for the population average examination score is between a lower limit of 67.35 and an upper limit of 85.05. The correct option is C.

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4 0
2 years ago
Question 25
IRINA_888 [86]
PLS HELP ASAP I DONT HAVE TIME AND IT ALSO DETECT IF ITS RIGHT OR WRONG! PLS HELP ASAP I DONT HAVE TIME AND IT ALSO DETECT IF ITS RIGHT OR WRONG!
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3 years ago
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