How do you do this problem
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Answer:
Probability that 100 or fewer of these Americans could only converse in one language is 0.8599.
Step-by-step explanation:
We are given that a recent study reported that 73% of Americans could only converse in one language.
A random sample of 130 Americans was randomly selected.
Let = <u><em>sample proportion of Americans who could only converse in one language.</em></u>
The z score probability distribution for sample proportion is given by;
Z = ~ N(0,1)
where, p = population proportion of Americans who could only converse in one language = 73%
= sample proportion =
= 0.77
n = sample of Americans = 130
Now, probability that 100 or fewer of these Americans could only converse in one language is given by = P(
0.77)
P(
0.77) = P(
) = P(Z
1.08) = <u>0.8599</u>
The above probability is calculated by looking at the value of x = 1.08 in the z table which has an area of 0.8599.