Answer:
Depending on how the input of each function defined,
- The first choice
, - The third choice
- The fourth choice
might be functions.
Step-by-step explanation:
A function between two sets (domain and range) should
- be defined for all elements in the domain, and
- map each element from the domain to exactly one element in the range.
The second choice can't be a function since the element 
from the domain is mapped to more than one element in the range.
Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be 
. Similarly, the domain for the third and fourth relations should be 
and 
Hey there!
One way to do this is find all the factors of 6 and then see which pair fit the requirements.
The factors of 6 are 1, 2, 3, and 6. (Note: There can be negative factors, but I am going to leave them out since it is asking for positive integers.)
You can find them by asking if each number can go into 6.
1, 2, 3, and 6 all go into 6, while 4 and 5 do not.
The requirements we have is that they must be consecutive <u>and</u> have a product of 6.
Consecutive means right after one another.
The only numbers that fit this are 2 and 3.
2 x 3 = 6
Hope this helps!
Answer:
p = 30/1/3 or 91/3 or 30.33
Step-by-step explanation:
2 + p = 7/3 + 30
p = 32/1/3 - 2
p = 30/1/3
Answer:
3n^2+9+5n^4+55n
Step-by-step explanation:
Steps
$\left(3n^2+9+5n^4-3n\right)+\left(-9n\left(-7\right)-5n\right)$
$\mathrm{Remove\:parentheses}:\quad\left(a\right)=a,\:-\left(-a\right)=a$
$=3n^2+9+5n^4-3n+9n\cdot\:7-5n$
$\mathrm{Add\:similar\:elements:}\:-3n-5n=-8n$
$=3n^2+9+5n^4-8n+9\cdot\:7n$
$\mathrm{Multiply\:the\:numbers:}\:9\cdot\:7=63$
$=3n^2+9+5n^4-8n+63n$
$\mathrm{Add\:similar\:elements:}\:-8n+63n=55n$
$=3n^2+9+5n^4+55n$
Answer:
I'm not sure the answer to this
