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erastova [34]
3 years ago
9

PLEASEE HELP MATHHH

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0
F(x) = -2x^2 - 3x + 5 for x = - 3
f(-3) = -2(-3)^2 -3(-3) + 5
f(-3) = -18 + 9 + 5
f(-3) = -4
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(8 + 4 X 3) x 6<br> 32 – 2 x3
kaheart [24]

Answer:

120 and 26

Step-by-step explanation:

  • ( 8 + 4 * 3 ) * 6

Using BODMAS rule,

[ 8 + ( 4 * 3 ) ] * 6

= ( 8 + 12 ) * 6

= 20 *6

= 120

  • 32 – 2 x 3

Using BODMAS rule,

32 - ( 2 * 3 )

= 32 - 6

= 26

Hope this answer was helpful!!

Regards..

4 0
2 years ago
Read 2 more answers
select all the sets that are the three side lengths of right triangles A.8,7,15 B.4, 10, √84 C. √8, 11, √129 D. √1, 2, √3
Semenov [28]

Answer:

<h3>B.4, 10, √84 </h3><h3>C. √8, 11, √129 </h3><h3>D. √1, 2, √3</h3>

Step-by-step explanation:

For any set of three side length of a triangle to be a right angled triangle, the sum of the square of the two of the sides must be equal to the square of the longest side according to pythagoras theorem.

The longest side is always the hypotenuse

For option D, 2 will be the longest side. Since 2 is the hypotenuse, the sum of the square of other two values must be equivalent to the square of 2,

= (\sqrt{1})^{2} +  (\sqrt{3})^{2} \\ = 1=3\\= 4\\= 2^{2} (hypotenuse)

This shows that √1, 2, √3 are three sides of a right triangles.

Similarly for option C, the hypotenuse is √129 being the largest.

To show the sides are that of a right triangles;

= (\sqrt{8}) ^{2} + 11^{2} \\= 8 + 121\\= 129\\= (\sqrt{129})^{2} \\

Since the resulting  value is the square of the hyp, then √8, 11, √129 are three sides of a right triangles.

For option B; 10 is the hypotenuse being the longest sides, To show the sides are that of a right triangles;

=4^{2}+(\sqrt{84})^{2} \\ = 16+84\\= 100\\= 10^{2}

Since the resulting  value is the square of the hyp, then 4, 10, √84  are three sides of a right triangles.

Only option A is wrong since 15² is not equal to the sum of 8² and 7².

4 0
3 years ago
In how many ways can 4 blue flags 3 green flags and 2 flags be arranged
DaniilM [7]
Assuming all of the same coloured flags are in<span>distinguishable,</span>

\text {Number of ways } =  \dfrac{9!}{4!3!2!} =  1260

--------------------------------
Answer: 1260 ways
--------------------------------
3 0
3 years ago
Mr. Gephart is traveling from his house to the history museum. How many meters will he travel to the museum? The distance from h
snow_lady [41]

Answer: 6700 meters

Step-by-step explanation:

From the question given, we are informed that Gephart is traveling from his house to the history museum and that the distance from home to the history museum is six and seven-tenths kilometers.

In order to know the distance in meters

that he will travel to the museum, we have to multiply the convert the distance given in kilometers to meters. This will be:

1000 meters = 1 kilometer

Therefore, 6 7/10km = (6 7/10 × 1000m)

= 6 7/10 × 1000

= 67/10 × 1000

= 67 × 100

= 6700 meters

He'll travel 6700 meters to the museum.

7 0
3 years ago
49 students are enrolled in health and 21 students are not what percentage of students in the school are in rolled in Health 
weeeeeb [17]

Answer:

im pretty sure its 30%. because 70% are in heath. so 30% of the students arent. i think... hope this helped.

Step-by-step explanation:

3 0
2 years ago
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