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3 years ago

For f (x) = 4 x +1 and g(x) = x^2- 5, find (g/f)(x)

Mathematics

1 answer:

Lady bird [3.3K]3 years ago

3 0

Answer:

The answer is: $\frac{x^2-5}{4x+1}$

Step-by-step explanation:

We are given: $f(x)=4x+1$ and $g(x) = x^2-5$

We need to find $(g/f)(x)$ .

Simply divide $g(x)$ and $f(x)\\$ .

Which equates to:

$(g/f)(x)= \frac{g(x)}{f(x)} =\frac{x^2-5}{4x+1}$

This cannot be simplified further, so it is the answer.

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PLS HELP QUICKLY !!!!!!

Olegator [25]

Answer: Choice C)

--------------------------------------

mean = xbar = (2400+1750+1900+2500+2250+2100)/6
mean = 2150

Subtract the data values from the mean to get

2400-2150 = 250
1750-2150 = -400
1900-2150 = -250
2500-2150 = 350
2250-2150 = 100
2100-2150 = -50
The differences are: 250, -400, -250, 350, 100, -50

Then you square those values and add up the squares

(250)^2 + (-400)^2 + (-250)^2 + (350)^2 + (100)^2 + (-50)^2 = 420,000

3 0

3 years ago

Read 2 more answers

Calcule o saldo de salário, o funcionário foi admitido em 10 de janeiro como mensalista, salário R$ 1400,00?

Sholpan [36]

Responda:

$ 980

Explicação passo a passo:

Dado que:

Salário mensal = $ 1400

Data de emprego = 10 de janeiro

Usando o sistema de mês de 30 dias:

Taxa diária =. $ 1400/30 = $ 46.66666

Dias não trabalhados = janeiro - 9 de janeiro = 9 dias

Subtraia o salário de 9 dias do total:

Salário total - (9 * taxa diária)

$ 1400 - (9 * $ 46,66666)

$ 1400 - $ 420

= $ 980

Portanto, o saldo do salário é de $ 980

7 0

2 years ago

The measure of angle A is 68°. The measure of angle B is 22°. Which statement best describes the relationship between these two

stellarik [79]

Answer:

They are complementary angles.

Step-by-step explanation:

The sum of their measurements equals 90 degrees.

3 0

2 years ago

What times 5 equals 75

saveliy_v [14]

15 the answer is 15 because 15 x 5 = 75

5 0

3 years ago

Read 2 more answers

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

4 0

3 years ago