Question

Find ∫^[infinity]_-[infinity] xe^-x^2 dx.

Answer 1

Answer:

Zero

Step-by-step explanation:

We are to find

$\int\limits^{infinity} _{-infinity} xe^-x^2 dx.$

Here the integral is of the form x varying from negative to positive

And negative limit = positive limit in dimension

Let us assume $f(x) =xe^{-x^2}$

A function is odd if f(x) = -f(-x) and even if f(x) = f(-x)

Let us check f(-x) = -f(x)

So f is an odd function.

As per properties of integration, we have

$\int\limits^a_{-a} {f(x)} \, dx$=0 if fis an odd function.

Our function f is odd and a = infinity

So we can apply this rule to find out the

integral value is zero.