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3 years ago

GOODNIGHT luvs!!!!! 1+1=3 lol just a lil humor

Mathematics

2 answers:

Yuliya22 [10]3 years ago

8 0

Answer:

Goodnight

Step-by-step explanation:

<3 don't stay up late and get rest !

tamaranim1 [39]3 years ago

4 0

Answer:

wow

Step-by-step explanation:

You might be interested in

Geoffrey is evaluating the expression (-3)^6(2^6)/(-3)^5(2^2) as shown below.

Alekssandra [29.7K]

Answer:

48.

Step-by-step explanation:

First you multiply the number by itself as many times as the number of the exponent is. In this case you multiply -3 to itself 6 times which makes -729, 2 to the 6th power is 64, -3 to the 5th power is -243, and 2 to the 2nd power is 4. Then you multiply -729 by 64 which makes -46656 and multiply -243 by 4 which makes -972, and then divide -972 from -46656 which makes 48.

3 0

3 years ago

1: A bag contains 10 white golf balls and 6 striped golf balls. A golfer wants to add 122 golf balls to the bag. He wants the ra

fgiga [73]

Part A:

Given that a bag contains 10 white golf balls and 6 striped golf balls, the ratio of white to striped golf balls is 10 : 6 = 5 : 3.

Given that a golfer wants to add 122 golf balls to the bag, the of balls each he should add is given by:

$5\left( \frac{122}{5+3} \right) \ : \ 3\left( \frac{122}{5+3} \right)=5\left( \frac{122}{8} \right) \ : \ 3\left( \frac{122}{8} \right) \\ \\ =5(15.25) \ : \ 3(15.25)=76.25 \ : \ 45.75 \\ \\ \approx76:46$

Therefore, the golfer shold add 76 white golf balls and 46 striped golf balls.

Part B.

You did not indicate the scale factor.

Assuming the scale factor is given by D(o, k) where k can be any number, then the cordinate of the coordinates of the image of the quadrilateral VWXY are given by:

V'(6k, 2k), W(-2k, 4k), X(-3k, -2k), Y(3k,-5k)

That is you multiply the scale factor to the coordinates of the preimage to get the coordinates of the image.

4 0

4 years ago

Solve the equation 2 sec² x = 3 - tan x for the domain 0° ≤ x ≤ 360°

vodka [1.7K]

$2 \sec^2 x = 3- \tan x \\\\\implies 2(1 +\tan^2 x) = 3- \tan x \\\\\implies 2 + 2 \tan^2 x +\tan x -3 =0\\\\\implies 2 \tan^2 x + \tan x -1 =0\\\\\implies 2u^2 + u -1 =0~~~ ;[\text{set} \tan x = u]\\\\\implies u = \dfrac{-1\pm \sqrt{1-4\cdot 2 \cdot (-1)}}{2(2)}\\\\\implies u =\dfrac{-1 \pm\sqrt{9}}{4}\\\\\implies u = \dfrac{-1 \pm 3}{4}\\\\\implies u = \dfrac{2}{4}=\dfrac 12~~ \text{or} ~~u =\dfrac{-4}{4} =-1\\\\$

$\implies \tan x = \dfrac 12 ~~ \text{or} ~~ \tan x =-1~~~ ;[\text{Substitute back u =tan x}]\\\\\text{Now,}~ \\\\\tan x = -1,\\\\\implies x = n\pi - \dfrac{\pi}4\\\\\\\text{For interval,}~ [0,2\pi) \\\\x = \dfrac{3\pi}4, \dfrac{7\pi}4\\\\\text{In degrees,}~ x = 135^{\circ}, x =315^{\circ}\\\\\tan x = \dfrac 12\\\\\implies x = n\pi + \tan^{-1} \left(\dfrac 12 \right)\\\\\text{For interval} ~[0,2\pi),\\\\$

$x=\tan^{-1} \left(\dfrac 12 \right), \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\text{in degrees,} ~~x=\tan^{-1} \left(\dfrac 12 \right), \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\\\\text{Combine all solutions:}\\\\x=\dfrac{3\pi}4, \dfrac{7\pi}4, \tan^{-1} \left(\dfrac 12 \right), \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\$

$\text{In degrees,}~ x = 135^{\circ},~315^{\circ},~\tan^{-1} \left(\dfrac 12 \right), \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]$

4 0

2 years ago

a cylinder water tank carries a volume of 150L when it is full. The water tank has a base surface with a diameter of 140 cm. wha

REY [17]

Answer:

9.74418019cm=h

~ 9.7442

Step-by-step explanation:

volume of a cylinder=πr²h

radius=½of diameter

=½×140cm

=70cm

1l=1000cm³

150l=150l/1l×1000cm³

=150000cm³

150000cm³=π(70cm)²×h

150000cm³=15393.8040cm²h

150000cm³/15393.8040cm²=15393.8040cm²h/15393.8040cm²

150000cm³/15393.8040cm²=h

9.74418019cm=h

7 0

3 years ago

What is the area of the shaded part of the figure if =14

aniked [119]

The area of the shaded part is: 42.14 ft² .

<h3>Area of Square</h3>

Area = s²

<h3>Area of Quarter Circle </h3>

Area = 1/4πr²

Thus:

Area of the shaded part of the figure = area of square - area of quarter circle

Area of shaded part = s² - 1/4πr²

s = 14 ft

r = 14 ft

Substitute

Area of shaded part = 14² - 1/4(3.14)(14²)

= 42.14 ft²

Therefore, the area of the shaded part is: 42.14 ft² .

Learn more about area of square on:

brainly.com/question/813881

4 0

2 years ago