Question

Simplify the following expression.

Answer 1

Answer:

The answer is cosx cot²x ⇒ the first answer

Step-by-step explanation:

∵ cot²x = cos²x/sin²x

∵ secx = 1/cosx

∴ cot²x secx - cosx = (cos²x/sin²x)(1/cosx) - cosx

  = (cosx/sin²x) - cosx

Take cosx as a common factor

∴ cosx[(1/sin²x) - 1] ⇒ use L.C.M

∴  cosx[1-sin²x/sin²x]

∵ 1 - sin²x = cos²x

∴ cosx(cos²x/sin²x) = cosx cot²x