Answer:
Our answer is 0.8172
Step-by-step explanation:
P(doubles on a single roll of pair of dice) =(6/36) =1/6
therefore P(in 3 rolls of pair of dice at least one doubles)=1-P(none of roll shows a double)
=1-(1-1/6)3 =91/216
for 12 players this follows binomial distribution with parameter n=12 and p=91/216
probability that at least 4 of the players will get “doubles” at least once =P(X>=4)
=1-(P(X<=3)
=1-((₁₂ C0)×(91/216)⁰(125/216)¹²+(₁₂ C1)×(91/216)¹(125/216)¹¹+(₁₂ C2)×(91/216)²(125/216)¹⁰+(₁₂ C3)×(91/216)³(125/216)⁹)
=1-0.1828
=0.8172
C temp. pH and regulatory molecules
Answer:
On the simulation prediction you got a 10% chance
While in the experimental one the average is 42%
48 cookies after 25 % decrease is as much as 75 % from 48:
75% from 48 =
= 75/100 * 48 =
= 3/4 * 48 =
= 3/1 * 12 =
= 3 * 12 =
= <u>36
</u>
I hope it will help you :)
