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beks73 [17]
4 years ago
11

The car has a constant deceleration of 4.20 m/s^2. If its initial velocity was 24.0 m/s, how long does it take to come to a stop

? Answer in s
Physics
1 answer:
nalin [4]4 years ago
5 0

Answer:

The time is 5.71 sec.

Explanation:

Given that,

Acceleration a= -4.20 m/s^2

Initial velocity = 24.0 m/s

We need to calculate the time

Using equation of motion

v = u+at[/tex]

Where, v = final velocity

u = inital velocity

t = time

a = acceleration

Put the value into the formula

0 =24.0 +(-4.20)\times t

t = \dfrac{-24.0}{-4.20}

t=5.71\ sec

Hence, The time is 5.71 sec.

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Explanation:

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The scientific question can be supported by evidence that must be true of the possible answers to a scientific question. Option D is correct,

<h3>What is a Scientific hypothesis?</h3>

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Hence option D is correct.

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6 0
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How can you show positive body languages with your mouth
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A beam of electrons passes through a single slit, and a beam of protons passes through a second, but identical, slit. The electr
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Answer:

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