Ask question

Ask question

All categories

3 years ago

8

our lab partner wears a new pair of sneakers to lab and, rather than performing the required experiments, you decide to measure

the coefficient of static friction they make with the lab floor. Your partner reports her mass to be 59.0 kg. Hooking up an industrial force sensor to your interface you give your partner a piece of rope attached to the sensor and begin to pull. When the sensor reads 318.3 N your partner starts to slip. Determine the coefficient of static friction between your partner and the floor.

1 answer:

Dafna1 [17]3 years ago

4 0

Answer:

The coefficient of static friction between your partner and the floor is 0.55

Explanation:

Given:

Mass $m = 59$ Kg

Frictional force $F_{s} = 318.3$ N

From the formula of frictional force,

$F_{s} = \mu_{s} mg$

Where $\mu _{s} =$ coefficient of static friction, $g = 9.8 \frac{m}{s^{2} }$

Put the above values and find the coefficient of static friction.

$318.3 = \mu_{s} \times 59 \times 9.8$

$\mu_{s} = 0.55$

Therefore, the coefficient of static friction between your partner and the floor is 0.55

You might be interested in

Two or more different monomers will link to form a

-BARSIC- [3]

d. natural gas is the answer

7 0

3 years ago

The waves shown below represent sound waves. Which of the waves would have the highest-pitched sound?

Ostrovityanka [42]

Humans hear frequencies from 20 Hz<span> (low) up to </span>20,000 Hz (high)

8 0

3 years ago

A war wolf is a device used during the middle ages to assault fortifications with large rocks. A simple trebuchet is constructed

Katarina [22]

Answer:v=41.23 m/s

Explanation:

Given

mass of heavy object $m_1=52 kg$

distance of $m_1$ from the axle $r_1=14 cm$

mass of rock $m_2=123 gm$

Length of rod $=4.1 m$

distance of $m_2$ from axle $r_2=4.1-0.14=3.96 m$

Net torque acting is

$T_{net}=m_1gr_1-m_2gr_2$

$T_{net}=52\times 0.14\times g-0.123\times 3.96\times g$

$T_{net}=6.793\times 9.8$

$T_{net}=66.57 N-m$

Work done by $T_{net}$ is converted to rock kinetic Energy

thus

$T_{net}\times \theta =\frac{mv^2}{2}$

Where $\theta =angle\ turned =\frac{\pi }{2}$

$v= velocity\ at\ launch$

$66.57\times \frac{\pi }{2}=\frac{0.123\times v^2}{2}$

$v^2=66.57\times \pi$

$v=\sqrt{1700.511}$

$v=41.23 m/s$

3 0

4 years ago

Describe a scenario when you could use energy but not do any work.

Harlamova29_29 [7]

Answer:

When you don't move, you still use energy. This energy is called potential energy, or, stored energy.

When you don't move or do work, you can use energy.

4 0

3 years ago

How to calculate time using power and energy

Troyanec [42]

Answer:

The formula that links energy and power is: Energy = Power x Time. The unit of energy is the joule, the unit of power is the watt, and the unit of time is the second.

Explanation:

7 0

3 years ago