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3 years ago

Can you help me please?! Is an emergency

Mathematics

1 answer:

anygoal [31]3 years ago

4 0

The answer is (mx+b)

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The limit as h approaches 0 of (e^(2+h)-e^2)/h is ?

Whitepunk [10]

If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
[e^(2+h) − e^2]/h = [e^2(e^h−1)]/h

so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:

=e^2

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3 years ago

What's 6 c ^ 2 + 2.5 D - D + 2C ^ 2 - 3D what is that simplified

adell [148]

I'm assuming that the lower case c and the upper case C are the same variables.

6C^2 + 2.5D - D + 2C^2 - 3D = 8C^2 - 1.5D

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4 years ago

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OverLord2011 [107]

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3 years ago

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Read the question and Write the function represented by the graph below 5x 2

liq [111]

Answer:

Step-by-step explanation:

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3 years ago

A commercial jet and a private airplane fly from Denver to Phoenix. It takes the commercial jet 1.1 hours for the flight, and it

FinnZ [79.3K]

Answer:

The speed of the private airplane is 770 mph, the speed of the commercial airplane is 980 mph.

Step-by-step explanation:

Let x mph be the speed of private airplane. If the speed of the commercial jet is 210 miles per hour faster than the speed of the private airplane, then the speed of commercial airplane is (x+210) mph.

It takes the commercial jet 1.1 hours for the flight, then it covered the distance of

$1.1(x+210)\ miles$

It takes the private airplane 1.8 hours for the flight, then it covered the distance of

$1.8x\ miles.$

The distances are the same, so

$1.1(x+210)=1.8x\\ \\1.1x+231=1.8x\\ \\1.8x-1.1x=231\\ \\0.7x=231\\ \\7x=2,310\\ \\x=770$

The speed of the private airplane is 770 mph, the speed of the commercial airplane is 770 + 210 = 980 mph.

3 0

3 years ago

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