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3 years ago

Help me please don’t use me for points

Mathematics

2 answers:

Norma-Jean [14]3 years ago

5 0

Answer:

9x+3

Step-by-step explanation:

First join the x terms, and you will find 9x (1x+8x), then join the numbers, and you get 3 (-7+10)

Hope it helps!

Romashka [77]3 years ago

3 0

Answer:

9x + 3

Step-by-step explanation:

given: 1x - 7 + 8x + 10

like terms: 1x + 8x - 7 + 10

solution: 9x + 3

some people might be confused about "1x + 8x - 7 + 10" bolded part. the minus sign beside 7 would become (-7), so adding (-7) + 10 will = 3

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The machine described has standard deviation σ that can be fixed at certain levels by carefully adjusting the machine. What is t

Gennadij [26K]

Answer:

σ = 0.5102

Step-by-step explanation:

Y = volume filled,

µ = mean

It is a normal distribution

It follows that

0.95 = P (|Y − µ| < 1) = P (|Z| < 1 / σ)

so that

1 / σ = 1.96 ⇒ σ = (1 / 1.96)

⇒ σ = 0.5102.

7 0

3 years ago

A piece of cloth is folded into a square with a side length measuring x inches. When it is unfolded, it has an area of x2 + 27x

marusya05 [52]

we have

$x^{2} + 27x + 162$

Using a graph tool------> to resolve the second order equation

the solution is

$x=-18\\ x=-9$

$x^{2} + 27x + 162=(x+18)*(x+9)$

therefore

the answer is the option

length = (x + 18) inches and width = (x + 9) inches

4 0

3 years ago

Read 2 more answers

A. Complete the chart based on the initial conditions:

Nata [24]

Answer:

$Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936$

$week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g$

Step-by-step explanation:

a. From the information provided, we can deduce that the population death's follows a Geometric sequence in the form $(a,ar,ar^2,ar^3...)$ where $a-first \ term$ and $r-common \ ratio$

#Since the population is reducing, $r$ can is obtained as $r=1-r=0.94$

#The $n^t^h$ term is obtained using the formula $x_n=ar^(^n^-^1^)$ , given a=1200

The number of ants alive after every month (in first 4 months)

The ant's alive after 4 months is obtained as the value of $x_5$

$x_n=ar^(^n^-^1^)\\1-x_5=1-1200\times 0.94^4=936.89\\\approx 936$

Hence, 936 ants are alive after 4 months.

b. As with the above question, the kitten population follows a geometric sequence: $(a,ar,ar^2,ar^3...)$ .

#Since it's a growing population , the common ration is the sum of 100% + the growth rate,

$r=1.1$ and $a=80$ and $x_n=ar^(^n^-^1^)$

The population after 4weeks will be:

$week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g$

8 0

3 years ago

Which is the best estimate of 174% of 141?

xeze [42]

245.34 is 174% of 141 :)
(1.74*141=245.34)

It helps to remember that "of" in math means to multiply. That's helped me for years.

4 0

3 years ago

Read 2 more answers

What is the solution(s) to the equation 5a^2 - 44 = 81

Alborosie

Answer:

a=5,a=-5