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Ulleksa [173]
3 years ago
12

Percent error Please Help

Mathematics
1 answer:
san4es73 [151]3 years ago
5 0

Answer:

2%

Step-by-step explanation:

Set up the problem with the numbers given to you

\frac{13.3 - 13.6}{13.6} x 100

-0.022058823529412 x 100

-2.205882352941176

Don't forget that it's absolute value and that you round to the nearest percent

2%

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Each day of the week mrs uses 3/4 of a gallon of gas what is the amount she uses in five days?
Andrej [43]

Answer:

3.75

Step-by-step explanation:

3/4 times 5 =3 3/4

8 0
1 year ago
Work out 140-3^2×(8+4)+6÷2
kiruha [24]

Answer:

140 - 9 (12) + 3

140 - 108 +3

140 - 111

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4 0
2 years ago
Find the indicated conditional probability
andrezito [222]

Given:

The two way table.

To find:

The conditional probability of P(Drive to school | Senior).

Solution:

The conditional probability is defined as:

P(A|B)=\dfrac{P(A\cap B)}{P(B)}

Using this formula, we get

P(\text{Drive to school }|\text{ Senior})=\dfrac{P(\text{Drive to school and senior})}{P(\text{Senior})}                      ...(i)

From the given two way table, we get

Drive to school and senior = 25

Senior = 25+5+5

           = 35

Total = 2+25+3+13+20+2+25+5+5

         = 100

Now,

P(\text{Drive to school and senior})=\dfrac{25}{100}

P(\text{Senior})=\dfrac{35}{100}

Substituting these values in (i), we get

P(\text{Drive to school }|\text{ Senior})=\dfrac{\dfrac{25}{100}}{\dfrac{35}{100}}

P(\text{Drive to school }|\text{ Senior})=\dfrac{25}{35}

P(\text{Drive to school }|\text{ Senior})=0.7142857

P(\text{Drive to school }|\text{ Senior})\approx 0.71

Therefore, the required conditional probability is 0.71.

5 0
3 years ago
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Answer:

Step-by-step explanation:

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