Since they are independent events to find the probability of both is P(A) * P(B)
P(A) = P(Heads) =
P(B) = P(Roll ≥ 4) =
Now multiply those fractions together
= P(Heads & ≥ 4)
Answer:
Step-by-step explanation:
Let's say the width is x. If the length is 3 meters more than the width, the the length is x+3.
A rectangle has 4 sides. 2 widths and 2 lengths. If the perimeter is 26 meters, you can plug in your expressions for the width and the length to solve for x.
2(x+3) +2(x)=26
2x+6+2x=26
4x+6=26
4x=20
x=5.
If x=5, that means that your with is 5 meters, and your length is 8 meters (5+3)
SA=201.7cm^2
I used the equation
SA=pi^1/3(6*V)^2/3 in case you have any more questions like this
Ab = (7x-6) → b = (7x-6)/a (1)
bc = (12-2x) → b = (12-2x)/c (2)
Since (1) = (2) → (7x-6)/a = (12-2x)/c OR a/c = (7x-6)/(12-2x) (3)
Multiply both numerators of (3) by the SQUARE of their respective denominators;
(a*c²)/c = (7x-6)(12-2x)²/(12-2x)
Now simplify:
ac = (7x-6)(12x-2x) or ac = -14x² + 96x - 72
