Identify the lateral area and surface area of a regular triangular pyramid with base edge length 14 cm and slant height 15 cm.

The accounting department analyzes the variance of the weekly unit costs reported by two production departments. A sample of 16

Sergio [31]

Answer:

We can conclude that the result is significant and production differ in cost variance.

Step-by-step explanation:

Given :

n1 = 16

n2 = 16

s1² = 5.7

s2² = 2.8

α = 0.10

H0 : σ1² = σ2²

H1 : σ1² ≠ σ2²

The test statistic :

Ftest = s1² / s2² =

Ftest = 5.7 / 2.8

Ftest = 2.036

Using the Pvalue from Fratio calculator :

df numerator = 16 - 1 = 15

df denominator = 16 - 1 = 15

Pvalue(2.036, 15, 15) = 0.0898

Pvalue = 0.0898

Since the Pvalue is < α ; We can conclude that the result is significant and production differ in cost variance.

3 0

3 years ago

10 to the zero power times 2 to the 1 power

bezimeni [28]

the answer is two :D

8 0

2 years ago

Lisa wrote the following statement: "You can only draw one unique isosceles triangle that contains an angle of 65°." Which state

JulijaS [17]

Triangles always equal 180 degrees

4 0

3 years ago

How do I solve this?

Sav [38]

It has no solution. The statement is false for any value x and y therefore the system of equations has no solution.

8 0

2 years ago

Identify the quadratic function(s). (Select all that apply.)

Katen [24]

General Idea:

The quadratic function of the form $ax^2+bx+c=0$ .

Applying the concept:

Simplifying the equation in option A, we get...

$A) \; 8 - 5x = 4(3x - 1) \\Distributing \; 4 \; in \; right \; side \; of \; the \; equation. \\ \\ 8 - 5x = 12x - 4\\ The \; equation \; is \; a \; linear \; equation \; with \; variable \; on \; both \; sides.$

Simplifying the equation in option B, we get...

$B) \; \; (4a + 2)(2a - 1) + 1 = 0\\ Multiplying \; First \; \; Outer \; \; Inner \; \; Last \; terms\; in\; the \; left \; side.\\ \\ 4a \cdot 2a + 4a \cdot -1 + 2 \cdot 2a + 2 \cdot -1 + 1 = 0\\ \\ 8a^2-4a+4a-2+1=0\\ Combining \; like \; terms \; \\ \\ 8a^2 - 1 = 0\\ Above \; is \; a \; Quadratic \; Equation!$

Simplifying the equation in Option C, we get...

$C)\; \; 2y + 2(3y - 5) = 0\\ Distributing \; 2 \; in \; left \; side\\ \\ 2y+6y-10=0\\ Combining \; like \; terms\\ \\ 8y - 10 = 0\\ Above \; Equation \; is \; linear \; equation$

Simplifying the equation in Option D, we get

$D) \;2b(b - 7) + b = 0\\ Distributing \; 2b\; in \;the \;left\; side \;of \;the\;equation\\ \\ 2b \cdot b - 2b \cdot 7+b=0\\ Simplify \; in \; the \; left \; side \; of \; the \; equation\\ \\ 2b^2-14b+b=0\\ Combine \; like \; terms\\ \\ 2b^2-13b=0\\ Above \; equation \;is \;a \; Quadratic\;Equation!$

<u>Conclusion:</u>

Option B) & Option D) are quadratic equation!

7 0

3 years ago

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