Are there rotations , transitions or reflections in a chair? ( Geometry 1 honors, I will mark brainly.) ASAP

Mathematics

1 answer:

Elena-2011 [213]4 years ago

3 0

Answer:

see below

Step-by-step explanation:

There are reflections in a chair. It really would depend on the chair. This chair would have a reflection along the y axis. I don't know of any chair with a translation.

Within a chair, we can have designs that are translations or rotations in the patterns of the fabric

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Please help me!!!!!!! :)

Lilit [14]

Hello there!

The answer is C.

I will explain to you how I came to this answer.

•First of all, I counted the turning points. There are two, so that means this polynomial function has THREE roots. (# of turning points+1=number of roots.)

•Next, look to see how many times the function crosses the x-axis. This is the number of REAL solutions. In this case, there is one point at which the f(x) is crossing the x-axis so there is one real solution.

•Since there is one real solution there has to be 2 imaginary roots. (Total # of solutions-real solutions=imaginary solutions)

NOTE: the turning points are where the increasing intervals change to decreasing and the decreasing change to increasing. The first derivative at these points is 0.

I hope this helps!
Best wishes~
-HuronGirl

3 0

4 years ago

Whats the answer of this problem 8-1*0+2/2=??

Reptile [31]

If I'm doing this right, I'm pretty sure the answer would be 7, since 0 + 1 = 1, 8 - 1 = 7, and 7 x 1 = 7.

I hope this answer helped you! If you have any further questions or concerns, feel free to ask! :)

3 0

3 years ago

Given a regular decagon, find the measures of the angles formed by (

Sonja [21]

A decagon has 10 sides (think decade and decathlon). From the center of the decagon we draw the radii and in doing so we take the area of the decagon and divide it into 10 congruent Triangles.

The angles around the center add up to 360 because they form a circle and since there are 10, they each measure 36 degrees. So the answer to the first part (the angle between the radii) is 36 degrees.

Each of these triangles has two equal sides (both radii) so is Isosceles. That means that the base angles are congruent. So the two angles that are left in each triangle must measure the same. Since the angles in a triangle add up to 180 degrees, we know that the two remaining angles are together equal to 180-36=144 degrees. Since they are equal in measure they each measure 72 degrees.

Thus the answer to the second part, trhe measure of the angle between a radius and the side of the polygon is 72 degrees.

3 0

3 years ago

WILL MARK BRAINLIEST what is the domain of (f/g) (x)?

tatyana61 [14]

Given that $f(x) = \sqrt{7-x}$ and $g(x) = \sqrt{x + 2}$ , we can say the following:

$\Bigg(\dfrac{f}{g}\Bigg)(x) = \dfrac{f (x)}{g(x)} = \dfrac{\sqrt{7 - x}}{\sqrt{x+2}}$

Now, remember what happens if we have a negative square root: it becomes an imaginary number. We don't want this, so we want to make sure whatever is under a square root is greater than 0 (given we are talking about real numbers only).

Thus, let's set what is under both square roots to be greater than 0:

$\sqrt{7 - x} \Rightarrow 7 - x \geq 0 \Rightarrow x \leq 7$

$\sqrt{x + 2} \Rightarrow x + 2 \geq 0 \Rightarrow x \geq -2$

Since both of the square roots are in the same function, we want to take the union of the domains of the individual square roots to find the domain of the overall function.

$x \leq 7 \,\,\cup x \geq -2 = \boxed{-2 \leq x \leq 7}$

Now, let's look back at the function entirely, which is:

$\Bigg( \dfrac{f}{g} \Bigg)(x) = \dfrac{\sqrt{7 - x}}{\sqrt{x+2}}$

Since $\sqrt{x + 2}$ is on the bottom of the fraction, we must say that $\sqrt{x + 2} \neq 0$ , since the denominator can't equal 0. Thus, we must exclude $\sqrt{x + 2} = 0 \Rightarrow x + 2 = 0 \Rightarrow x = -2$ from the domain.