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Angelina_Jolie [31]
2 years ago
8

Please help fast, thanks.

Mathematics
1 answer:
Sav [38]2 years ago
3 0

Answer:

b > 100

Step-by-step explanation:

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PLS HELP WITH THIS!!!!!
Butoxors [25]

Answer:

c

Step-by-step explanation:

4 0
3 years ago
Clare is in charge of getting snacks for a road trip with her friends and her dog. She has
Eduardwww [97]

Answer:

$15 and 50 cents

Step-by-step explanation:

3.25x2=6.50+9=15.50

6 0
3 years ago
Read 2 more answers
A bag of chocolates is labeled to contain 0.384 pound of chocolates. The actual weight of the chocolates is 0.3798 pound. Are th
taurus [48]

Answer:

The answer to your question is the chocolates are slightly lighter than the weight stated on the label.

Step-by-step explanation:

Data

The label says 0.384 pounds

Actual mass = 0.3798 pounds

Process

To solve this problem the only thing we must do is substrate the actual weight of chocolates to the weight of chocolates stated on the label.  

If the result is positive, then the chocolates are lighter  

If the result is negative, then the chocolates are heavier

          0.384 pounds - 0.3798 pounds = 0.0042

hmu if you need sumin els!

5 0
3 years ago
Read 2 more answers
My monthly cell phone bill is $40 plus $.10 for each text message. Write an equation to show the cost of texting. What is my tot
Otrada [13]

Answer:

y=.1x+40; Your total monthly bill is $48 for 80 text messages.

Step-by-step explanation:

y is your total bill

x represents each text message

40 is you cellphone bill cost

.1 is the cost per text message

(y=.1x+40 becomes your equation)

plug 80 to represent "x"

y=.1*80+40 --->  y=48

your total monthly bill is $48

8 0
3 years ago
In 2010, the average duration of long-distance telephone calls originating in one town was 9.4 minutes. A long-distance telephon
Zepler [3.9K]

<u>Answer</u>: No, we do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.

Step-by-step explanation:

As per given , we have

H_0: \mu=9.4\\\\H_a:\mu\neq9.4, since H_0 is two-tailed so , the test is a two tail test.

Since population standard deviation is unknown, so we use t-test.

Critical value (two-tailed) for significance level of 0.01= t_{n-1,\alpha/2}=t_{49, 0.005}\pm2.609228

For n =50 , \overline{x}=8.6 and s= 4.8

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

t=\dfrac{8.6-9.4}{\dfrac{4.8}{\sqrt{50}}}\approx-1.18

Since test statistic value (-1.18) lies in critical interval (-2.609228, 2.609228), it means the null hypothesis is failed to reject.

We do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.

4 0
3 years ago
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