3 years ago

Simplify. 9√5−7√5+√7

Mathematics

1 answer:

kramer3 years ago

7 0

2√5+√7..............<span>

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Find the 5th term of the expansion of ( 6x + 6y)^11

Elodia [21]

The 5 th term of the given expression is 330 $(6x)^{7}( 6y)^{4}$ .

Step-by-step explanation:

Given,

$(6x+6y)^{11}$

To find the 5th term of the given expression.

Formula

In a binomial series $(a+b)^{n}$ , the r th term is = nC(r-1) $a^{n-r-1} b^{r-1}$ , where,

nC(r-1) = $\frac{n!}{(r-1)!(n-r+1)!}$

Now,

Putting, n=11, r = r, a=6x and b=6y we get,

5 th term = 11C4 $(6x)^{7}( 6y)^{4}$

= $\frac{11!}{4!7!}$ $(6x)^{7}( 6y)^{4}$

= $\frac{11X10X9X8X7!}{7!X4X3X2X1}$ $(6x)^{7}( 6y)^{4}$

= 330 $(6x)^{7}( 6y)^{4}$

Here is the answer.

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2 years ago