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Pepsi [2]
3 years ago
9

Is this right? i’ll give brainliest :)

Mathematics
2 answers:
jek_recluse [69]3 years ago
6 0

It is.

x-10 \geq 0\\\\x \geq 10\\\\\\-5 +n< -6\\\\n < 5-6\\\\n< -1

Dennis_Churaev [7]3 years ago
4 0

Answer:

Correctomundo!

Step-by-step explanation:

For x-10 > 0:

1. Add 10 to both sides. x- 10 + <u><em>10</em></u> > 0 + <u><em>10</em></u>

<u><em /></u>

x > 10

For -5 + n < -6:

1. Simplify both sides of the inequality.  n - 5 < -6

2. Add 5 to both sides. n - 5 + <em><u>5</u></em> < -6 + 5

n < -1

:)

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What is the inverse of f(x)=x^4+7 for x&gt;0 where function g is the inverse of function f?<br> -
Ann [662]

Answer:

g(x) = \sqrt[4]{x-7},~ x\geq 7

Step by step explanation:

y= f(x) = x^4+7\\\\\text{Replace x with y and solve for y:}\\\\~~~~~~~x = y^4 +7\\\\\implies y^4 = x-7\\\\\implies y = \pm\sqrt[4]{x-7}\\\\ \implies f^{-1}(x) = \pm\sqrt[4]{x-7}

7 0
2 years ago
Find the 52nd term of the following arithmetic sequence.<br> 17, 22, 27, 32, ...
rewona [7]

Answer:

17; 22; 27; 32

the terms increase by 5 each time

17 + 5 = 22 (the second term)

17 + 5 * 2 = 27 (third term)

So to get to the 52nd term, we have to add 5* 51 = 255 to 17

17 + 255 = 272

Step-by-step explanation:

4 0
3 years ago
Assume you have such a watch. if a minimum of 18.0% of the original tritium is needed to read the dial in dark places, for how m
laila [671]
Given that the half life of 3H is 12.3 years.

The amount of substance left of a radioactive substance with half life of t_{ \frac{1}{2} } after t years is given by

N(t)=N_0\left(\frac{1}{2} \right)^{ \frac{t}{t_{\frac{1}{2}} }

Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

18 \% = 100 \% \left(\frac{1}{2} \right)^{ \frac{t}{12.3}} \\  \\ \Rightarrow\left(\frac{1}{2} \right)^{ \frac{t}{12.3}} =0.18 \\  \\ \Rightarrow\frac{t}{12.3}\ln\left(\frac{1}{2} \right)=\ln0.18 \\  \\ \Rightarrow\frac{t}{12.3}= \frac{\ln0.18}{\ln\left(\frac{1}{2} \right)} = \frac{-1.715}{-0.6931} =2.474\\ \\ \Rightarrow t=2.474(12.3)=30.4

Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>
5 0
3 years ago
The first term in a sequence is 3<br> The term-to-term rule is + 8<br> What is the 5th term?
galben [10]
2nd term: 3+8
= 11
3rd term: 11+8
= 19
4th term: 19+8
= 27
5th term: 27+8
= 35


OR
((n-1)x8)+3
7 0
3 years ago
What would this be?:)
Mnenie [13.5K]

Answer:

\d

Step-by-step explanation:

:)

3 0
3 years ago
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