Given:

To find:
The number of possible solutions, if the Order of Operations did not exist.
Solution:
We have,

Now,
Case 1:
![[4 + 9 + 16] \div [4 - 8 -(3 \times 5)]=29\div (4 - 8 -15)](https://tex.z-dn.net/?f=%5B4%20%2B%209%20%2B%2016%5D%20%5Cdiv%20%5B4%20-%208%20-%283%20%5Ctimes%20%205%29%5D%3D29%5Cdiv%20%284%20-%208%20-15%29)

Case 2:
![[4 + 9 + 16] \div (4 - 8 -3) \times 5=29\div (-7\times 5)](https://tex.z-dn.net/?f=%5B4%20%2B%209%20%2B%2016%5D%20%5Cdiv%20%20%284%20-%208%20-3%29%20%5Ctimes%20%205%3D29%5Cdiv%20%20%28-7%5Ctimes%205%29)

Case 3:


Many more possibilities are there.
Therefore, there are more than 3 possible solutions.
Answer:
x = 10
Step-by-step explanation:
Make x the subject
2x - 8 = 12
2x = 12 + 8
2x = 20
x = 20/2
x = 10
!!