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saul85 [17]
3 years ago
9

What is the constant of proportionality

Mathematics
2 answers:
IceJOKER [234]3 years ago
8 0

Answer:

2.5

Step-by-step explanation:

From the above, we see clearly that as x increase, y also increase. This means that y is directly proportional to x. With this understanding, we can calculate the constant(K) as illustrated below:

y & x

y = Kx

K = y / x

When x = 2, y = 5

K = 5/2 = 2.5

Stolb23 [73]3 years ago
3 0

Answer:

The constant of proportionality is 2.5

Step-by-step explanation:

if i helped plz be kind to mark me as brainliest

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Use the table to find the slope.<br><br><br> -2<br><br><br> 2<br><br><br> 1/2<br><br><br> -1/2
Tresset [83]

Answer:

going upp then downn

Step-by-step explanation:

3 0
3 years ago
The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m  + 40 m  + c = 120 m

61 m +  c = 120 m

c = 120 m - 61 m

c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

                ↓                                       ↓

            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

8 0
3 years ago
20 PTSS !!!<br> PLEASE HELPP !!
butalik [34]

Because it is extremely hard to find the area of this figure all together, it would be in our best interest to split this figure up into three different pieces: the two horizontal rectangles, and the verticle rectangle. We can find the area of all three and add them up. Be aware that there are two different ways that you can break this figure up, As shown in the attachments. I will be using the first image (the one with the tall horizontal rectangles, NOT the almost-squares).

So, we see that we have enough information to solve for the area of the left-most rectangle. Area = lw. 10 x 4 = 40, so the area is 40. Next, we have to notice, that the horizontal rectangles are also the same, so both of the areas of the two horizontal rectangles are 40.

Now, we can find the middle rectangle. We know that the length of the entire thing is 18, but it is taken up by 8 (4+4) of the horizontal triangles, so 18-8=10, so the length Is 10. We also know that the height of the horizontal rectangles is 10, so 10-3=7. Our dimensions for the rectangle are 10x7 or 70 square units. If we add them all together, 40+40+70=150.

The area is 150 square units

8 0
3 years ago
What is the radius of the circle given by the equation (x-2)^2+y^2=14
Rainbow [258]
The general equation of a circle is
 (x-a) ^ 2 + (y-b) ^ 2 = r ^ 2
 for this case the values of a and b are
 a = 2
 b = 0
 The radius of the circle is
 r ^ 2 = 14
 r = (14) ^ (1/2) = 3.74

8 0
3 years ago
Just answer #2 plz for brainlest
AlexFokin [52]

n>-6 and n<3 (there's your answer my friend)

8 0
3 years ago
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