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2 years ago

Which polynomials are in standard form

Mathematics

1 answer:

artcher [175]2 years ago

7 0

Answer:

Step-by-step explanation:

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Yumi and Juan pick up litter along the highway at the same rate. Yumi picks up litter for 3 miles and takes two hours longer tha

Harlamova29_29 [7]

3/(x+2) = 2/x

multiply both fractions by x(x+2) to cancel out the bottoms

so it becomes 3x = 2x+4

ow subtract 2X from both sides and you get

x = 4

so it took Juan 4 hours

it took Yumi 2 hours more so 4+2 = 6 hours

7 0

2 years ago

Read 2 more answers

Suppose Z Varies directly with x and inversely with y, where x = 16, y = 4, when z = 32...............

Greeley [361]

A.)
Z = kx/y where k is a constant.
32 = 16k/4
k = 128/16
k = 8

z = 8x/y

b.)
Z = 8(21)/6
Z = 28

c.)
4 = 8x/48
x = 192/8
x = 24

6 0

2 years ago

Read 2 more answers

Help me 7th grade math please

Stolb23 [73]

Answer: 13.5 ounce bottle for $2.19

a 29.2 ounce bottle for $5.37

The 29.2 ounce bottle is better

Step-by-step explanation:

13.5 ounce bottle for $2.19

a 29.2 ounce bottle for $5.37

find the ratios

13.5/2.19 = $6.16 per unit

29.2/5.37 = $5.44 per unit

3 0

1 year ago

Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an

Natasha_Volkova [10]

Answer:

The volume of the solid is 243 $\sqrt{2} \ \pi$

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0 ≤ ρ² ≤ 81

0 ≤ ρ ≤ 9

The intersection that takes place in the sphere and the cone is:

$x^2 +y^2 ( \sqrt{x^2 +y^2 })^2 = 81$

$2(x^2 + y^2) =81$

$x^2 +y^2 = \dfrac{81}{2}$

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

$z = \sqrt{x^2+y^2}$

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; $\dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}$

Thus, volume: $V = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4} \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho ^2 \ sin \phi \ d\rho \ d \theta \ d \phi$

$V = \int \limits^{\pi/2}_{\pi/4} \ sin \phi \ d \phi \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho ^2 d\rho$

$V = \bigg [-cos \phi \bigg]^{\pi/2}_{\pi/4} \bigg [\theta \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3} \bigg ]^{9}_{0}$

$V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]$

V = 243 $\sqrt{2} \ \pi$

4 0

2 years ago

SHOW YOUR WORK!!<br><br> What is the distance between point A (-3, -2) and Point B (4, -7)?

gulaghasi [49]

Answer: $\bold{\sqrt{74}}$

<u>Step-by-step explanation:</u>

$\text{Use the distance formula: }d_AB=\sqrt{(x_A-x_B)^2+(y_A-y_B)^2}\\where\ (X_A, y_A)=(-3, -2)\\and\ (x_B,y_B)=(4, -7)\\\\\\d_AB=\sqrt{(-3-4)^2+[-2-(-7)]^2}\\\\.\quad =\sqrt{(-7)^2+(5)^2}\\\\.\quad =\sqrt{49+25}\\\\.\quad =\boxed{\sqrt{74}}$

3 0

3 years ago