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Sergio039 [100]
3 years ago
10

Which polynomials are in standard form

Mathematics
1 answer:
artcher [175]3 years ago
7 0

Answer:

C

Step-by-step explanation:

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If f(x) = 2x – 6 and g(x) = x – 22, find each value.
Charra [1.4K]

Answer:

Step-by-step explanation:

I think you made a typo. g(x) should equal x - 2 not x - 22

g(x) =  x - 2

g(-1) = -1 - 2

g(-1) = - 3

The answer is d. Otherwise there is no answer.

7 0
2 years ago
Can someone help me with 1-3
mina [271]
1 would be D.
2. Is A since 3^2=9 and -3^2=9 And 9-9=0. Im pretty sure A. For number 3. Just because the two x-values are 3 and -3. I’m sorry if I’m wrong on #3.
8 0
3 years ago
Solve the equality 2(4x+1 )< 3(2x-3)
Musya8 [376]

Answer:

Step-by-step explanation:

2(4x+1)<3(2x-3)

simplify to

8x+2<6x-9

we can add 9 to both sides and subtract 8x from both sides

11<-2x

divide by -2

-5.5>x

7 0
2 years ago
Select all that apply.
lord [1]

Answer:

improved mental health

decreased risk of alcohol and drug use

3 0
3 years ago
Read 2 more answers
A 40-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and the chain
daser333 [38]

Answer:

a) W₁ = 78400 [J]

b)Wt = 82320 [J]  

Step-by-step explanation:

a) W = ∫ f*dl      general expression for work

If we have a chain with density of 10 Kg/m, distributed weight would be

9.8 m/s² * 10 kg   = mg

Total length of th chain is 40 m, and the function of y at any time is

f(y) = (40 - y ) mg   where ( 40 - y ) is te length of chain to be winded

At the beggining we have to wind 40 meters   y = 0 at the end of the proccess  y = 40 and there is nothing to wind then:

f(y) = mg* (40 - y )

W₁ =  ∫f(y) * dy    ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy  ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy

W₁ = mg [ 40*y |₀⁴⁰   -  1/2 * y²  |₀⁴⁰    ⇒  W₁ = mg* [ 40*40 - 1/2 (40)² ]

W₁ = mg * [1/2]     W₁ = 10*9,8* ( 800 )

W₁ = 78400 [J]

b) Now we can calculate work to do if we have a 25 block and the chain is weightless

W₂ = ∫ mg* dy     ⇒    W₂  = ∫₀⁴⁰ mg*dy   ⇒    W₂  = mg y |₀⁴⁰

W₂ = mg* 40   = 10*9.8* 40  

W₂ = 3920 [J]

Total work

Wt = W₁  +  W₂        ⇒    Wt = 78400 + 3920

Wt = 82320 [J]

6 0
3 years ago
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