<span>the probability the coach selects all girls is m</span>ost likely
Answer:
- <u>No, he can get an output of 0 with the second machine (function B) but he cannot get an output of 0 with the first machine (function A).</u>
Explanation
The way each machine works is given by the expression (function) inside it.
<u>1) </u><em><u>Function A</u></em>
To get an output of 0 with the function y = x² + 3, you must solve the equation x² + 3 = 0.
Since x² is zero or positive for any real number, x² + 3 will never be less than 3 (the minimum value of x² + 3 is 3). So, it is not possible to get an output of 0 with the first machine.
<u>2) </u><em><u>Function B</u></em>
Solve 
So, he can get an output of 0 by using x = 4.
Answer:
21y^2+11.2
Step-by-step explanation:
4-3y(-7y)+7.2
combine like terms
-3y (-7y) = 21y^2
add 4 to 7.2
11.2
21y^2 + 11.2
Answer:
n=9
Explanation:
First, let's give a name to the number we are looking for and call it n.
So we can then write "A number is divided by 3" as n3
To add 5 to the quotient would then give us the expression n3+5
If this results in 8 we can finally write the equation we are trying to solve and solve the equation for n while keeping the equation balanced:
n3+5=8
n3+5−5=8−5
n3+0=3
n3=3
3⋅n3=3⋅3
1n=9
n=9