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galben [10]
3 years ago
12

Graph the relation shown in the table. Is the relation a function? Why or why not?

Mathematics
1 answer:
Brut [27]3 years ago
5 0

Answer:

C

Step-by-step explanation:

There are 2 of -1s and they are both on the x axis which there for means that it would be a vertical line going up and down for 2 points at the -1

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Can someone help me with these problems and explain them as well please
olga_2 [115]

Answer:

b=112°

Step-by-step explanation:

two complementary angles

b=180°-68°=112°

sum of 2 angles is

x= 35°+25°=60°

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What is 5x-9=7x+6-2x
Sliva [168]
-9 = -6 is your answer
4 0
3 years ago
I suck at math please help lol
sasho [114]

Answer:

1

Step-by-step explanation:

since the 2 functions equal each other:

-2x + 3 = 4x - 9

add -2x to both sides

3 = 6x - 9

add 9 to both sides

12 = 6x

divide by 6

2 = x

you have x, now find y, you just need to plug 2 into one of the equations instead of both bc they both equal the same anyway

-2(2) + 3

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7 0
3 years ago
The weekly amount of money spent on maintenance and repairs by a company was observed, over a long period of time, to be approxi
VikaD [51]

Answer:

$512.90 should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with mean $480 and standard deviation $20.

This means that \mu = 480, \sigma = 20

How much should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05?

This is the 100 - 5 = 95th percentile, which is X when Z has a pvalue of 0.95, so X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 480}{20}

X - 480 = 1.645*20

X = 512.9

$512.90 should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05

5 0
3 years ago
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