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svlad2 [7]
3 years ago
13

Please help on 12! And tell me how to do it please!

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
5 0
4.5x ft^2

Length times height is area. Area is always measure in squares, in this case: square feet.
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What’s the answer pleazzzzz helplllllll 9m^2-4m-6 by 3m
dlinn [17]

Answer

D. 3m - 4/3 -2/m


<u>Explanation</u>

(9m²-4m-6) ÷ 3m  = 9m²/3m - 4m/3m - 6/3m

Carry out the division, each term is divided by 3m.

9m²/3m = 3m

- 4m/3m = -4/3

- 6/3m = - 2/m

Finally you will get,

<em>3m - 4/3 -2/m</em>

5 0
3 years ago
A marine aquarium has a small tank and a large tank, each containing only red and blue fish. In each tank, the ratio of red fish
Anna007 [38]

Answer:

Ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

Step-by-step explanation:

Let the number of red fish and blue fish in the large tank are x and y respectively.

Similarly ratio of red fish and blue fish in the small tank are x' and y' respectively.

Since in each tank ratio of the red fish to blue fish is 333 : 444

That means x : y = 333 : 444

Or \frac{x}{y}=\frac{333}{444}

⇒ \frac{x}{y}=\frac{3}{4}

⇒ y = \frac{4x}{3} --------(1)

Similarly x' : y' = 333 : 444

⇒ \frac{x'}{y'}=\frac{333}{444}

⇒ \frac{x'}{y'}=\frac{3}{4}

⇒ x' = \frac{3y'}{4} ------(2)

Ratio of the fish in large tank to the fish in small tank is 464646 : 555

So (x + y) : (x' + y') = 464646 : 555

\frac{x+y}{x'+y'}=\frac{464646}{555}

Now we replace the values of x and y' from equation (1) and equation (2)

\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}

\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}

\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}

\frac{x}{y'}=\frac{3}{4}\times \frac{464646}{555}

\frac{x}{y'}=\frac{232323}{370}

\frac{y'}{x}=\frac{370}{232323}

\frac{y'}{x}=\frac{10}{6279}

Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

4 0
4 years ago
I’m giving out brainlest to whoever answers this correctly!
borishaifa [10]

Answer:

A. 18.2

Step-by-step explanation:

b^2 + 14^2 = 23^2

b = sqrt(333) = 18.248

5 0
3 years ago
When the full season tickets first went on sale,2,000 Full season tickets sold for Section N. Two weeks after the tickets first
slega [8]

Image showing the arena ticket prices is missing, so i have attached it.

Answer:

$10000 more money was spent when the tickets first went on sale than after the first 2 weeks

Step-by-step explanation:

We are told that when the full season tickets first went on sale, that 2000 full season tickets were sold for section N.

Now, from the area ticket prices table attached, we can see that full season tickets for Section N costs $20

Thus, amount of money spent when the tickets first went on sale = 2000 × 20 = $40000

We are told that 2 weeks after the tickets first went on sale, they sold 1500 tickets. Thus, amount spent after 2 weeks release = 1500 × 20 = $30000

Difference in amount spent at the beginning and after 2 weeks = $40000 - $30000 = $10000

Thus, $10000 more money was spent when the tickets first went on sale than after the first 2 weeks

6 0
3 years ago
How would you solve this?
siniylev [52]

Answer:

Step-by-step explanation:

hello :

(x-4)²(x+3)² = -1

means : ((x-4)(x+3))² = - 1 this equation has no solutions in R

because for all x in R : ((x-4)(x+3))² ≥ 0

3 0
3 years ago
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