(8+15+8+3+12)/2+1=24th number will be median
So median is gonna be 21
I'm assuming that when you wrote "(7x/2-5x+3)+(2x/2+4x-6)," you actually meant "<span>(7x^2-5x+3)+(2x^2+4x-6). Correct me if I'm wrong here.
</span><span>+(7x^2-5x+3)
</span><span>+(2x/2+4x-6)
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=9x^2 - x - 3 (answer) </span>
x = number of 1-cent stamps
y = number of 8-cent stamps
z = number of 12-cent stamps
We have 31 stamps all together, so x+y+z = 31.
"I have 4 more 1-cent stamps than 8-cent stamps" means we have the equation x = y+8. Whatever y is, add 8 to it to get x. Solve for y to get y = x-8.
You also have "twice as many one cent stamps as 12 cent stamps", so x = 2z. Solving for z gets you z = 0.5x
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x+y+z = 31
x+x-8+z = 31 ... y replaced with x-8
x+x-8+0.5x = 31 ... plug in z = 0.5x
2.5x-8 = 31
2.5x = 31+8
2.5x = 39
x = 39/2.5
x = 15.6
Your teacher made a typo somewhere because we should get a positive whole number result for x (since x is a count of how many 1-cent stamps we have).
Answer:
(-12, -1)
Step-by-step explanation:
(8, -1) => (-2/3x, f(-2/3x))
therefore
-2/3x = 8
x = 8 *-3/2
x = -12
f(-2/3x) = -1
therefore, the corresponding point is:
(-12,-1)
Step-by-step explanation:
There are 7 books that can go in the first spot.
After a book has been placed in the first spot, there are 6 books left that can go in the second spot.
After that, there are 5 books that can go in the third spot.
So on and so forth.
So the number of ways is:
7×6×5×4×3×2×1 = 7! = 5040