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JulijaS [17]
3 years ago
10

Which of the following correctly describes the difference between arteries and veins?        A. Veins carry oxygenated blood, wh

ile arteries carry blood low in oxygen  B. Arteries carry blood to the heart, veins carry blood away from the heart  C. Arteries carry oxygenated blood, while veins carry blood low in oxygen
Health
2 answers:
Levart [38]3 years ago
5 0

Answer:

The correct answer would be C, Arteries carry oxygenated blood while veins carry blood low in oxygen.

Explanation:

Arteries are the tubes made up of muscles which take the blood to the heart after the process of oxygenation. Oxygenation is the process in which the blood is purified and then transferred to the heart through arteries. Veins are the part of blood circulation system. These are the tubes, which carry blood which are low in oxygen, or we can say that veins carry oxygen depleted blood to different parts of the body. So this is the main difference that arteries contain fully oxygenated blood while veins contain oxygen depleted blood.

Varvara68 [4.7K]3 years ago
3 0

Answer:

C.  Arteries carry oxygenated blood, while veins carry blood low in oxygen

Explanation:

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Differentiate the following functions (i) x(1+x)^3​
statuscvo [17]

Answer:

\displaystyle y' = (1 + x)^2(4x + 1)

General Formulas and Concepts:

<u>Algebra I</u>

  • Terms/Coefficients
  • Functions
  • Function Notation
  • Factoring

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative Property [Addition/Subtraction]:                                                                \displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                                \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Derivative Rule [Chain Rule]:                                                                                       \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Explanation:

<u>Step 1: Define</u>

<em>Identify</em>

y = x(1 + x)³

<u>Step 2: Differentiate</u>

  1. Product Rule [Derivative Rule - Chain Rule]:                                                  \displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot \frac{d}{dx}[1 + x]
  2. Derivative Property [Addition/Subtraction]:                                                    \displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot (\frac{d}{dx}[1] + \frac{d}{dx}[x])
  3. Basic Power Rule:                                                                                             \displaystyle y' = x^{1 - 1} \cdot (1 + x)^3 + x \cdot 3(1 + x)^{3 - 1} \cdot (0 + x^{1 - 1})
  4. Simplify:                                                                                                             \displaystyle y' = (1 + x)^3 + 3x(1 + x)^2
  5. Factor:                                                                                                               \displaystyle y' = (1 + x)^2 \bigg[ (1 + x) + 3x \bigg]
  6. Combine like terms:                                                                                         \displaystyle y' = (1 + x)^2(4x + 1)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

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