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Delvig [45]
3 years ago
7

What is the solution to the inequality 0.8x+20<1.2x−40?

Mathematics
1 answer:
LuckyWell [14K]3 years ago
3 0

Answer:x=150

Step-by-step explanation:

Step 1: Subtract 1.2x from both sides.

0.8x+20−1.2x=1.2x−40−1.2x

−0.4x+20=−40

Step 2: Subtract 20 from both sides.

−0.4x+20−20=−40−20

−0.4x=−60

Step 3: Divide both sides by -0.4.

−0.4x

−0.4

=

−60

−0.4

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Evaluate 48/6-10/3 please and thank you :)))
vodomira [7]

Answer:

14/3

Step-by-step explanation:

Simplify the following:

48/6 - 10/3

Hint: | Reduce 48/6 to lowest terms. Start by finding the GCD of 48 and 6.

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Hint: | Put the fractions in 8 - 10/3 over a common denominator.

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5 0
3 years ago
Please answer question 4
olasank [31]
#4)
cross multiply
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Evaluate the expression<br> cos(30°)=
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cos(30°) = √1 – sin230°

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