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adoni [48]
3 years ago
13

29. Each day, two out of the three teams in a class are randomly

Mathematics
1 answer:
diamong [38]3 years ago
7 0

Answer:

2/3

Step-by-step explanation:

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If $1,000 is invested at 16% interest, compounded annually,
Harrizon [31]

Answer:

equation; P=A(1+r/n)^nt

P=principal amount

A=value of investment

r= interest rate in decimals

n=number of times compounded

t=time in years

P=1000(1+0.16/12)^12(5)= $2213.8 rounded

Step-by-step explanation:

8 0
3 years ago
A package contains 12 resistors, 3 of which are defective. If 4 are selected, find the probability of getting
s344n2d4d5 [400]

Answer:

Incomplete question, but I gave a primer on the hypergeometric distribution, which is used to solve this question, so just the formula has to be applied to find the desired probabilities.

Step-by-step explanation:

The resistors are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

12 resistors, which means that N = 12

3 defective, which means that k = 3

4 are selected, which means that n = 4

To find an specific probability, that is, of x defectives:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = x) = h(x,12,4,3) = \frac{C_{3,x}*C_{9,4-x}}{C_{12,4}}

7 0
3 years ago
Determine if the relationship is a function & explain why and why not.
padilas [110]
No the following coordinates do not show a function because of the y-values. In the pairs that you have, (3,5) and (0,5) have the y-values of "5" that are repeating.

Hope this helps. I learned that in math.
5 0
3 years ago
It's possible to build a triangle with a side lengths of 5, 5, and 10
yawa3891 [41]
Yeah, base is ten and the two sides are 5...
7 0
3 years ago
Read 2 more answers
Complete the proof. What is reason #5?
Darya [45]

Statements

2. right triangle

3. PQ = OP

5. ∆ONP = ∆PQO

Reasons

1. Given

4. Given

5. SAS

<em><u>hope </u></em><em><u>this</u></em><em><u> answer</u></em><em><u> helps</u></em><em><u> you</u></em><em><u> dear</u></em><em><u> </u></em><em><u>take</u></em><em><u> care</u></em><em><u> </u></em><em><u>and </u></em><em><u>may</u></em><em><u> u</u></em><em><u> have</u></em><em><u> a</u></em><em><u> great</u></em><em><u> day</u></em><em><u> ahead</u></em><em><u>!</u></em>

4 0
3 years ago
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