Flight 4358 took off from the DFW airport at an elevation of 48°. If the airplane has been traveling for 1200 ft., approximately
how far above the ground is the airplane?
1 answer:
Answer:
891.77 feet
Step-by-step explanation:
since it is not stated, i'm going to assume that 1200 feet is the actual distance the plane travels along the 48° elevation. (i.e its the hypotenuse)
(see attached sketch)
we can see that the elements of the diagram form a right triangle, this means that we can use trigonometry to solve for the elevation x,
sin (48°) = x / 1,200
x = 1,200 sin (48°)
x = 891.77 feet
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