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kotykmax [81]
3 years ago
7

Can someone help me understand the concept of finding the domain and range on a graph. I don’t understand it! Someone help me

Mathematics
1 answer:
juin [17]3 years ago
5 0

Answer:

The Domain is where the line on your graph crosses the X axis.

The Range us where the line on your graph crosses the Y axis

And a arrow means it goes Into infinity

Step-by-step explanation:

Say you Have a line, it crosses the X axis at -3, your Domain would be -3!

Now say this line crosses the Y axis at -6, Your Range would be -6!

And now say if instead of the line ending at a dot after crossing -6 It has a arrow, that means you have infinity, Making your range instead of -6 it's be infinity! (If the arrow points up it's positive infinity, If the arrow points down it's negative infinity)

So for the first 2 numbers your answer would be [-3,-6] and in you have infinity itd be [-3, infinity) parenthesis isn't a error btw if you still don't get it I can just reply with a sheet I have on it

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Use logarithmic differentiation to find dy/dx
liq [111]

Answer:

dy/dx  =  (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]

Step-by-step explanation:

y = (x^2 - 3)^sinx

ln y = ln  (x^2 - 3)^sinx

ln y = sin x * ln (x^2 - 3)

1/y * dy/dx  =   sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x

1/y dy/dx =  2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)

dy/dx  =   [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y

dy/dx  =  (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]

7 0
3 years ago
Help needed please! *will mark as brainliest if correct
Svet_ta [14]
2 gophers per day are getting removed
6 0
3 years ago
Ryan can text 22 words in 4 minutes. At this rate, how many words could he text in 12 minutes? Fill out the table of equivalent
aleksandrvk [35]
The answer would be 66
Explanation: first you have to divide the minutes so 12 divided by 4 equals 3 so you would take the three and multiply that by 22. So 22x3 is equal to 66
3 0
3 years ago
Write down the explicit solution for each of the following: a) x’=t–sin(t); x(0)=1
Kay [80]

Answer:

a) x=(t^2)/2+cos(t), b) x=2+3e^(-2t), c) x=(1/2)sin(2t)

Step-by-step explanation:

Let's solve by separating variables:

x'=\frac{dx}{dt}

a)  x’=t–sin(t),  x(0)=1

dx=(t-sint)dt

Apply integral both sides:

\int {} \, dx=\int {(t-sint)} \, dt\\\\x=\frac{t^2}{2}+cost +k

where k is a constant due to integration. With x(0)=1, substitute:

1=0+cos0+k\\\\1=1+k\\k=0

Finally:

x=\frac{t^2}{2} +cos(t)

b) x’+2x=4; x(0)=5

dx=(4-2x)dt\\\\\frac{dx}{4-2x}=dt \\\\\int {\frac{dx}{4-2x}}= \int {dt}\\

Completing the integral:

-\frac{1}{2} \int{\frac{(-2)dx}{4-2x}}= \int {dt}

Solving the operator:

-\frac{1}{2}ln(4-2x)=t+k

Using algebra, it becomes explicit:

x=2+ke^{-2t}

With x(0)=5, substitute:

5=2+ke^{-2(0)}=2+k(1)\\\\k=3

Finally:

x=2+3e^{-2t}

c) x’’+4x=0; x(0)=0; x’(0)=1

Let x=e^{mt} be the solution for the equation, then:

x'=me^{mt}\\x''=m^{2}e^{mt}

Substituting these equations in <em>c)</em>

m^{2}e^{mt}+4(e^{mt})=0\\\\m^{2}+4=0\\\\m^{2}=-4\\\\m=2i

This becomes the solution <em>m=α±βi</em> where <em>α=0</em> and <em>β=2</em>

x=e^{\alpha t}[Asin\beta t+Bcos\beta t]\\\\x=e^{0}[Asin((2)t)+Bcos((2)t)]\\\\x=Asin((2)t)+Bcos((2)t)

Where <em>A</em> and <em>B</em> are constants. With x(0)=0; x’(0)=1:

x=Asin(2t)+Bcos(2t)\\\\x'=2Acos(2t)-2Bsin(2t)\\\\0=Asin(2(0))+Bcos(2(0))\\\\0=0+B(1)\\\\B=0\\\\1=2Acos(2(0))\\\\1=2A\\\\A=\frac{1}{2}

Finally:

x=\frac{1}{2} sin(2t)

7 0
3 years ago
Consider an election with 681 votes a) If there are 5 candidates, what is the smallest number of first-place votes a candidate c
joja [24]

Answer:

137 votes

Step-by-step explanation:

considering an election with 681 votes and 5 candidates up for the election

dividing the votes among'st 5 candidates

= 681 / 5 = 136.2  hence the least number of first-place votes needed by a candidate using the plurality method  would be = 137 votes

136.2 + 136.2 + 136.2 + 136.2 + 136.2 = 681 ( dividing the votes equally )

136 + 136 + 136 + 136+136 = 680

hence the remaining vote = 681 - 680 = 1

least first-place vote = 136 + 1 = 137 votes

6 0
3 years ago
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