All categories

3 years ago

2(4w-1)=-10(w-3)+4 help

Mathematics

2 answers:

solniwko [45]3 years ago

7 0

Answer:

w = 12

Step-by-step explanation:

2(4w-1)=-10(w-3)+4

2*4w + 2*-1 = (10*w + 10*-3) + 4

8w - 2 = 10w - 30 + 4

8w - 2 = 10w - 26

26 - 2 = 10w - 8w

24 = 2w

w = 24/2

w = 12

Check:

2((4*12)-1) = 10(12-3) + 4

2(48-1) = 10(9) + 4

2*47 = 90 + 4 = 94

zalisa [80]3 years ago

7 0

Step-by-step explanation:

$2 \times 4w - 2 \times 1 = 10 \times w - 10 \times 3 + 4 \\ 8w - 2 = 10w - 30 + 4 \\ collect \: like \: terms \\ 8w - 10w = - 30 + 4 + 2 \\ - 2w = - 24 \\ divide \: both \: side \: by \: - 2 \\ - 2w \div - 2 = - 24 \div - 2 \\ w = 12$

You might be interested in

If Elisa gets an allowance of $35 per week and spends $10 of it on food and drink, $5 on entertainment and $5 on miscellaneous t

Maslowich

Answer:

15$

Step-by-step explanation:

35-10=25$

25-5=20$

20-5=15$

6 0

3 years ago

Help me please !!!!!!!!!!!!!!

tensa zangetsu [6.8K]

Answer:

$\large\boxed{V=\dfrac{49\pi}{3}\ in^3}\approx51.29\ in^3}$

Step-by-step explanation:

The formula of a volume of a cone:

$V=\dfrac{1}{3}\pi r^2H$

r - radius

H - height

We have

r = (7 : 2) in = 3.5 in

H = 4 in

Substitute:

$V=\dfrac{1}{3}\pi(3.5)^2(4)=\dfrac{1}{3}\pi(12.25)(4)=\dfrac{49\pi}{3}\ in^3$

$\pi\approx3.14\\\\V\approx\dfrac{(49)(3.14)}{3}\approx51.29\ in^3$

5 0

3 years ago

Please help (Its multiple choice)

artcher [175]

Step-by-step explanation:

-5(4a) = (-5a)4

(By commutative property of multiplication)

4 0

3 years ago

Read 2 more answers

Evaluate the following integral in cylindrical coordinates triple integral 1/(1+x^2+y^2) dzdxdy z=0..2 y=0..square root(1-x^2) x

sertanlavr [38]

In cylindrical coordinates, we take

$x=r\cos\theta$

$y=r\sin\theta$

$z=z$

so that $\mathrm dx\,\mathrm dy\,\mathrm dz=r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz$ .

We have

$1+x^2+y^2=1+r^2$

and the integral is

$\displaystyle\int_0^2\int_0^\pi\int_0^1\frac r{1+r^2}\,\mathrm dr\,\mathrm d\theta\,\mathrm dz=\frac{\ln2}2\int_0^2\int_0^\pi\mathrm d\theta\,\mathrm dz=\boxed{\pi\ln2}$

8 0

3 years ago

53 POINTS PLEASE HELP AND BRAINLYIST!!!

klemol [59]

Answer:

Dilations.

Step-by-step explanation:

A dilation does not preserve congruency since the post-image will be of a different size than the pre-image.

6 0

3 years ago

Read 2 more answers