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pochemuha
3 years ago
9

Henry is playing with a standard deck of cards. What is the probability that the next card he flips over is a jack or red?

Mathematics
1 answer:
Anastasy [175]3 years ago
6 0

Answer:

0.54

Step-by-step explanation:

In Probability "OR" means "ADDITION" and "AND" means "MULTIPLICATION"

Here, we want probability of Jack "OR" Red, so we find individual probabilities and then "ADD" them.

There are 26 cards that are RED, half of the deck. So probability of RED CARD is:

P(red) = 26/52 = 1/2

Now, there are 4 Jacks in the whole deck, 2 red Jack and 2 black Jack. We already accounted for the 2 red jacks, so we have 2 black Jacks at hand. So

P(Jack) = 2/52 = 1/26

Now, we add the 2 probabilities:

P(jack or red) = 1/2 + 1/26 = 13/26 + 1/26 = 14/26 = 0.54 (rounded to 2 decimal places)

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HELP ME PLEASEE
Nina [5.8K]

Answers:

x = -8/5 or x = 8/5

Sum of the first ten terms where all terms are positive = 4092

========================================================

Explanation:

r = common ratio

  • first term = 4
  • second term = (first term)*(common ratio) = 4r
  • third term = (second term)*(common ratio) = (4r)*r = 4r^2

The first three terms are: 4, 4r, 4r^2

We're given that the sequence is: 4, 5x, 16

Therefore, we have these two equations

  • 5x = 4r
  • 4r^2 = 16

Solve the second equation for r and you should find that r = -2 or r = 2 are the only possible solutions. If r = -2, then 5x = 4r solves to x = -8/5. If r = 2, then 5x = 4r solves to x = 8/5.

-----------------

To find the sum of the first n terms, we use this geometric series formula

Sn = a*(1 - r^n)/(1 - r)

We have

  • a = 4 = first term
  • r = 2, since we want all the terms to be positive
  • n = 10 = number of terms to sum up

So,

Sn = a*(1 - r^n)/(1 - r)

S10 = 4*(1 - 2^10)/(1 - 2)

S10 = 4*(1 - 1024)/(-1)

S10 = 4*(-1023)/(-1)

S10 = 4092

8 0
2 years ago
Help me pleaseeee with this question
kenny6666 [7]

Answer:

B. 7

Step-by-step explanation:

Count every number less than 70 (count the leaf plot numbers if that helps).

62,62,63,64,54,56,56 = 7 drivers that travel less than 70 mph

8 0
2 years ago
An article includes the accompanying data on compression strength (lb) for a sample of 12-oz aluminum cans filled with strawberr
Sliva [168]

Answer:

A) Option B is correct.

H₀: μ₁ = μ₂

Hₐ: μ₁ - μ₂ < 0

B) t = -2.502

p-value = 0.0112

C) Option A is correct.

Reject H₀. The data suggests that cola has a higher average compression strength than the strawberry drink.

D) Option A is correct.

The distributions of compression strengths are approximately normal.

Step-by-step explanation:

The complete Question is presented in the two attached images to this answer.

A) To perform this test we first define the null and alternative hypothesis.

The null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test.

While, the alternative hypothesis usually confirms the the theory being tested by the experimental setup. It usually contains the signs ≠, < and > depending on the directions of the test.

For this question, we want to test if the extra carbonation of cola results in a higher average compression strength. That is, that cola has a higher average compression strength than the strawberry drink.

Hence, the null hypothesis would be that there isn't significant evidence to suggest that the extra carbonation of cola results in a higher average compression strength, that is, cola has a higher average compression strength than the strawberry drink.

The alternative hypothesis is that there is significant evidence to suggest that the extra carbonation of cola results in a higher average compression strength, that is, cola has a higher average compression strength than the strawberry drink.

Mathematically, if the average compression strength of strawberry drink is μ₁, the average compression strength of cola is μ₂ and the difference in compression strengths is μ = μ₁ - μ₂

The null hypothesis is represented as

H₀: μ = 0 or μ₁ = μ₂

The alternative hypothesis is represented as

Hₐ: μ < 0 or μ₁ - μ₂ < 0

B) So, to perform this test, we need to compute the test statistic

Test statistic for 2 sample mean data is given as

Test statistic = (μ₁ - μ₂))/σ

σ = √[(s₂²/n₂) + (s₁²/n₁)]

μ₁ = average compression strength of strawberry drink = 537

n₁ = sample size of the sample of strawberry drink in cans surveyed = 10

s₁ = standard deviation of the compression strength of strawberry drink in cans surveyed= 22

μ₂ = average compression strength of cola = 559

n₂ = sample size of the sample of cola in cans surveyed = 10

s₂ = standard deviation of the compression strength of strawberry drink in cans surveyed = 17

σ = [(17²/10) + (22²/10)] = 77.5903160379 = 8.792

We will use the t-distribution as no information on population standard deviation is provided

t = (537 - 559) ÷ 8.792

= -2.502 = -2.50

checking the tables for the p-value of this t-statistic

Degree of freedom = df = n₁ + n₂ - 2 = 10 + 10- 2 = 18

Significance level = 0.05

The hypothesis test uses a one-tailed condition because we're testing in only one direction (whether compression strength of cola in can is greater).

p-value (for t = -2.50, at 0.05 significance level, df = 18, with a one tailed condition) = 0.011154 = 0.0112 to 4 d.p.

C) The interpretation of p-values is that

When the (p-value > significance level), we fail to reject the null hypothesis and when the (p-value < significance level), we reject the null hypothesis and accept the alternative hypothesis.

So, for this question, significance level = 0.05

p-value = 0.0112

0.0112 < 0.05

Hence,

p-value < significance level

This means that we reject the null hypothesis accept the alternative hypothesis & say that the extra carbonation of cola results in a higher average compression strength, that is, cola has a higher average compression strength than the strawberry drink.

D) The necessary conditions required before a t-test is deemed valid include.

- The samples used must be a random sample of the population distribution with each variable in the sample independent of other one.

- The distribution of the population where the samples were extracted from must be normal or approximately normal to ensure some degree of normality for the samples.

Hence, the necessary assumption for this t-test among the options is that the distributions of compression strengths are approximately normal.

Hope this Helps!!!

7 0
3 years ago
Hank bought 2.4 pounds of apples each pound cost $1.95 how much money was spent on the apples
skad [1K]
The total would be $4.68. It is $0.78 for 0.4 of a pound, and you multiply $1.95 two times aqnd add that to the $0.78
3 0
3 years ago
Read 2 more answers
The data in the table is describing the heights of the Boston Celtics.
tester [92]

Answer: 4.5%

Step-by-step explanation:

Percentage will be calculated as:

No of players with height below 74/ total number of players x 100

From the question, Only one player has height of below 74

Total number of heights recorded is from 22 players

% = 1/22 × 100

0.04545 x 100

= 4.5%

I hope this helps.

5 0
3 years ago
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