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Nutka1998 [239]
3 years ago
6

Let f (x)=x-2 and g(x)=x to the second power -7x-9.find f (g(-1))

Mathematics
1 answer:
Degger [83]3 years ago
5 0

f(g(-1)) = - 3

Evaluate g(-1) and substitute into f(x)

g(-1) = (-1)² -7(-1) - 9 = 1 + 7 - 9 = - 1

f(g(-1)) = (-1) - 2 = - 3


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Write standard form of line that is parallel to 2x + 3y= 4 and passes through the point (1, -4)
Tresset [83]

Answer:

2x + 3y = -10

Step-by-step explanation:

First convert the line into slope intercept form to find the slope of the line.

2x + 3y = 4

3y = 4 - 2x

y = -2/3x + 4/3

The slope of the line is -2/3. Parallel lines have the same slope so the slope for a line through the point (1,-4) will be -2/3. Substitute m = -2/3 and (1,-4) into the point slope of a line.

y --4 = -\frac{2}{3}(x-1)\\y + 4 = -\frac{2}{3}(x -1)

Now convert the line into standard form by using the distributive property.

y + 4 = -\frac{2}{3}(x -1)\\y + 4 = -\frac{2}{3}x + \frac{2}{3}\\3y + 12 = -2x + 2\\2x + 3y + 12 = 2\\2x + 3y = -10

4 0
4 years ago
the second term in a geometric sequence is 20. the fourth term in the same sequence is 45/5, or 11.25. what is the common ratio
Karo-lina-s [1.5K]

Answer:21

Step-by-step explanation:becausebecausebecau se i know

8 0
4 years ago
Francesca has 281 marbles in her collection.Tothe nearest hundred about how many marbles does Francesca have ?
evablogger [386]
Francesca will have 300 marbles
6 0
4 years ago
For p = $3000, r = 3.5%,and t = 5 years, Find the balance in an account When interest is compounded (a) quarterly, (b) monthly,a
MAVERICK [17]

Answer:

a) $3,571.02

b) $3,572.9

c) $3,573.74

Step-by-step explanation:

Data provided in the question:

p = $3000,

r = 3.5%,

t = 5 years

a) quarterly

number of periods in a year, n = 4

Interest rate per period = 3.5% ÷ 4 = 0.875%

Now,

A = p\times \left( 1 + \frac{r}{n} \right)^{\Large{n \cdot t}}

A = total amount

n = number of times compounded per year

on substituting the respective values, we get

A = 3000 × \left( 1 + \frac{ 0.035 }{ 4 } \right)^{\Large{ 4 \cdot 5 }}

A = 3000 × [/tex]\cdot { 1.00875 } ^ { 20 }[/tex]

A = 3000 × 1.19034

A = $3,571.02

b) monthly

number of periods in a year, n = 12

Now,

A = p\times \left( 1 + \frac{r}{n} \right)^{\Large{n \cdot t}}

on substituting the respective values, we get

A = 3000 × \left( 1 + \frac{ 0.035 }{ 12 } \right)^{\Large{ 12 \cdot 5 }}

A = 3000 × [/tex]\cdot { 1.002917} ^ { 60 }[/tex]

A = 3000 × 1.190967

A = $3,572.9

c) continuously

A = pe^{r\times t}

on substituting the respective values, we get

A = 3,000 × e^{0.035\times 5}

or

A = 3,000 × e^{0.175}

or

A = 3,000 × 1.1912

or

A = $3,573.74

5 0
3 years ago
Read 2 more answers
What is the area of the main circle of stones at Stone Henge?
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I’ve noticed you have the right formula, do you have a radius?
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