The third term of the expansion is 6a^2b^2
<h3>How to determine the third term of the
expansion?</h3>
The binomial term is given as
(a - b)^4
The r-th term of the expansion is calculated using
r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)
So, we have
3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)
Evaluate the sum and the difference
3rd term = C(4, 2) * (a)^2 * (-b)^2
Evaluate the exponents
3rd term = C(4, 2) * a^2b^2
Evaluate the combination expression
3rd term = 6 * a^2b^2
Evaluate the product
3rd term = 6a^2b^2
Hence, the third term of the expansion is 6a^2b^2
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a and c i think
the blue circle is all the people who had brothers one name was in the blue circle so one person had a brother but the in between part of the too circles are who had both a brother and a sister so the is one name in the between purple so you count that one to for brother and for sisters
there were 2 people that had brother
and four people that had sisters
and one that had both
The answer to the problem is:
<span>8j^3 + 5j^2 - 3 - 5j^3 - 7j^2 + 12j - 7
</span>
<span>3j^3 - 2j^2 + 12j - 10
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
Answer:
There are 10 hours and 45 minutes until the bus leaves.
Answer:
A) T = -1.
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
10t+4−2t=2−2(t+4)
10t+4+−2t=2+(−2)(t)+(−2)(4)(Distribute)
10t+4+−2t=2+−2t+−8
(10t+−2t)+(4)=(−2t)+(2+−8)(Combine Like Terms)
8t+4=−2t+−6
8t+4=−2t−6
Step 2: Add 2t to both sides.
8t+4+2t=−2t−6+2t
10t+4=−6
Step 3: Subtract 4 from both sides.
10t+4−4=−6−4
10t=−10
Step 4: Divide both sides by 10.
Hope this helps!
:)
:)
:)
-Josh
