Answer:
88
Step-by-step explanation:
Write the expression for the sum in the relation you want.
Sn = u1(r^n -1)/(r -1) = 2.1(1.06^n -1)/(1.06 -1)
Sn = (2.1/0.06)(1.06^n -1) = 35(1.06^n -1)
The relation we want is ...
Sn > 5543
35(1.06^n -1) > 5543 . . . . substitute for Sn
1.06^n -1 > 5543/35 . . . . divide by 35
1.06^n > 5578/35 . . . . . . add 1
n·log(1.06) > log(5578/35) . . . take the log
n > 87.03 . . . . . . . . . . . . . . divide by the coefficient of n
The least value of n such that Sn > 5543 is 88.
Answer:
D. 60=(x+45)
Step-by-step explanation:
They are the same degree so they should equal eachother
1. (x-7)(x-4)
2. (x-12)(x+7)
use foil to check your work
Answer:
10 percent
Step-by-step explanation:
Answer:
y = x + 2
Step-by-step explanation:
The expression x-2 is from the equation y = x - 2.
To find the inverse of the equation, <u>switch the "x" and "y" variables</u>, then solve or <u>isolate for "y"</u>, meaning to separate it from the other numbers.
y = x - 2 Original equation
x = y - 2 Switched "x" and "y" variables
x + 2 = y - 2 + 2 Add 2 to both sides to cancel out '-2' on the side with "y"
x + 2 = y
y = x + 2 Variable is on left side in standard formatting
To isolate, do the reverse operation for the number you want to get rid of.
On the side with "y", I wanted to get rid of '-2' so I could separate "y" from everything else. '+2' is the reverse operation for '-2'.
